1000cm to m

Name: Solved: 1000cm to m - MathMaster
Brand: MathMaster
Rating: 4.9 (50 reviews)

likes

252 views

Answer to a math question 1000cm to m

$Expert avatar$

Dexter

4.7

114 Answers

1. Recognize the conversion factor:

1 \, \text{m} = 100 \, \text{cm}

.
2. Convert 1000 cm to meters by dividing by 100:

1000 \, \text{cm} \div 100 = 10 \, \text{m}

Answer:

10 \, \text{m}

Frequently asked questions (FAQs)

Question: What is the integral of f(x) = 2x^2 - 3x + 4 from x = 1 to x = 4?

Math question: What is the 4th higher-order derivative of f(x) = 3x^5 - 2x^3 + 4x^2 - 7x + 2?

What is the value of x in log₄(x) = 2?

New questions in Mathematics

Let f(x)=||x|−6|+|15−|x|| . Then f(6)+f(15) is equal to:

Let the vectors be u=(-1,0,2) , v=(0,2,-3) , w=(2,2,3) Calculate the following expressions a)<u,w> b) <2u- 5v,3w>

A circle with a 12-inch diameter is folded in half and then folded in half again. What is the area of the resulting shape?

Solve: −3(−2x+23)+12=6(−4x+9)+9.

Determine all solutions to the inequality |2x + 6| − |x + 1| < 6. Write your final answer in interval notation

(-5/6)-(-5/4)

-27=-7u 5(u-3)

The physician orders 15mg of tramadol(liquid). On hand is 30mg/2mL vials. How many mL will the MA administer?

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.2 in. Find P95. That is, find the hip breadth for men that separates the smallest 95% from the largest 5%.

Use a pattern to prove that (-2)-(-3)=1

9 x² + 2x + 1 = 0

2x2

Two particles of electrical charges Q1=3.8×10-⁶C and q,=4.4×10-⁶C are separated in vacuum by a distance of 4.0.10-⁸ m. Since K=9.0.10⁹ N.m²/C², the intensity of the interaction force between them, in newtons, is?

Calculate the change in internal energy of a gas that receives 16000 J of heat at constant pressure (1.3 atm) expanding from 0.100 m3 to 0.200 m3. Question 1Answer to. 7050J b. 2125J c. None of the above d. 2828J and. 10295 J

For the numbers below, select a number at random and find the probability that: a. The number is even b. The sum of the number’s digit is even c. The number is greater than 50 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97

Consider the function f(x)=1/2(x+1)^2-3. Use the preceding/following interval method to estimate the instantaneous rate of change at 𝑥 = 1.

56 × 12 = 672. How should you adjust this answer 672 to determine 57 × 12? a) The answer increases by 1 b) The answer increases by 57 c) The answer increases by 56 d) The answer increases by 12

Sodium 38.15 38.78 38.5 38.65 38.79 38.89 38.57 38.59 38.59 38.8 38.63 38.43 38.56 38.46 38.79 38.42 38.74 39.12 38.5 38.42 38.57 38.37 38.71 38.71 38.4 38.56 38.39 38.34 39.04 38.8 A supplier of bottled mineral water claims that his supply of water has an average sodium content of 36.6 mg/L. The boxplot below is of the sodium contents levels taken from a random sample of 30 bottles. With this data investigate the claim using SPSS to apply the appropriate test. Download the data and transfer it into SPSS. Check that your data transfer has been successful by obtaining the Std. Error of the mean for your data which should appear in SPSS output as 0.03900.. If you do not have this exact value, then you may have not transferred your data from the Excel file to SPSS correctly. Do not continue with the test until your value agrees as otherwise you may not have correct answers. Unless otherwise directed you should report all numeric values to the accuracy displayed in the SPSS output that is supplied when your data has been transferred correctly. In the following questions, all statistical tests should be carried out at the 0.05 significance level. Sample mean and median Complete the following concerning the mean and median of the data. mean = mg/L 95% CI: to mg/L Based upon the 95% confidence interval, is it plausible that the average sodium content is 36.9 mg/L? median: mg/L The median value is 36.9 mg/L. Skewness Complete the following concerning the skewness of the data. Skewness statistic = Std. Error = The absolute value of the skewness statistic less than 2 x Std. Error Therefore the data can be considered to come from a population that is . Normality test Complete the following summary concerning the formal testing of the normality of the data. H0: The data come from a population that normal H1: The data come from a population that normal Application of the Shapiro-Wilk test indicated that the normality assumption reasonable for sodium content (S-W( )= , p= ). Main test Using the guidelines you have been taught that consider sample size, skewness and normality, choose and report the appropriate main test from the following ( Appropriate ONE ) You have selected that you wish to report the one-sample t-test. H0: The mean sodium content equal to 36.9 mg/L H1: The mean sodium content equal to 36.9 mg/L Application of the one-sample t-test indicated that the mean is 36.9 mg/L (t( ) = , p = ). You have selected that you wish to report the Wilcoxon signed rank test. H0: The median sodium content equal to 36.9 mg/L H1: The median sodium content equal to 36.9 mg/L Application of the Wilcoxon signed rank test indicated that the median is 36.9 mg/L (z = , N = , p = ).

The supply of a good registers periodic increases. With each increase in the offer, the total receipts of the bidders increase. Indicate the correct statement: a) demand is elastic b) demand is inelastic c) supply is inelastic d) supply has unit elasticity.

A gas is leaking at 3.5ft3/min in a room of 2.9m by 6.9ft by 15.7m. How long would it take (in seconds) for 22% of the room to reach the LFL, if the gas has a LFL of 2.51%?

1000cm to m

Answer to a math question 1000cm to m

You might be interested in