1. Expand both sides of the equation:
10x + 2(x - 6) = 3(4x - 4)
10x + 2x - 12 = 12x - 12
2. Combine like terms:
12x - 12 = 12x - 12
3. Subtract \(12x\) from both sides:
-12 = -12
which is always true. Therefore, the equation (10x + 2(x - 6) = 3(4x - 4)) holds true for all values of (x). This means the equation is an identity and is necessarily true for any (x).