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2x ^2 - 9x - 2 = 0

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Answer to a math question 2x ^2 - 9x - 2 = 0

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Seamus
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$2x^{2}-9x-2=0$
$x=\frac{-\left(-9\right)Β±\sqrt{\left(-9\right)^{2}-4\times 2\left(-2\right)}}{2\times 2}$
$x=\frac{-\left(-9\right)Β±\sqrt{81-4\times 2\left(-2\right)}}{2\times 2}$
$x=\frac{-\left(-9\right)Β±\sqrt{81-8\left(-2\right)}}{2\times 2}$
$x=\frac{-\left(-9\right)Β±\sqrt{81+16}}{2\times 2}$
$x=\frac{-\left(-9\right)Β±\sqrt{97}}{2\times 2}$
$x=\frac{9Β±\sqrt{97}}{2\times 2}$
$x=\frac{9Β±\sqrt{97}}{4}$
$x=\frac{\sqrt{97}+9}{4}$
$x=\frac{9-\sqrt{97}}{4}$
$x=\frac{\sqrt{97}+9}{4},\frac{9-\sqrt{97}}{4}$

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