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3 2a 1 2 5a 1 4 3a 4
Question
3(2a-1) - 2(5a+1)=4(3a+4)
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Answer to a math question 3(2a-1) - 2(5a+1)=4(3a+4)
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$3(2a-1)-2(5a+1):{\quad}-4a-5$
$-4a-5=12a+16$
Move
$ 5 $
to the right side
$-4a=12a+21$
Move
$ 12a $
to the left side
$-16a=21$
Divide both sides by
$-16$
$a=-\frac{21}{16}$
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yββ -4yβ +4y = (12x^2 -6x)e^2x Y(0)= 1 Yβ(0)=0 Y(x)=c1y1+c2y2+yp