3IxI-2 greater than or equal to -10

1. Add 2 to both sides of the inequality:
3|x| - 2 + 2 \geq -10 + 2
3|x| \geq -8

2. Divide both sides by 3:
|x| \geq -\frac{8}{3}

3. Since the absolute value is always non-negative and the right-hand side is negative,
the inequality |x| \geq -\frac{8}{3} is always true for any real number.

[Satisfies for All Reals]
x \in \mathbb{R}