Question
A 50 kg box slides down an inclined plane 8.3 m long and 4 m high. If the friction force between the box and the inclined plane is 112 N, what is the work done by the friction force?
257
likes1286 views
Answer to a math question A 50 kg box slides down an inclined plane 8.3 m long and 4 m high. If the friction force between the box and the inclined plane is 112 N, what is the work done by the friction force?
Madelyn
4.786 Answers
Solución:
El trabajo realizado por la fuerza de fricción está dado por
W_f=fd
dónde
f es la fuerza de fricción entre el objeto y la superficie, y
d es la distancia recorrida por el objeto.
Según el teorema de Pitágoras, la distancia recorrida es
d=\sqrt{x^2+y^2}
d=\sqrt{8.3^2+4^2}
d\aproximadamente9.214m
Por tanto, el trabajo realizado es
W_f=112\cdot9.214
W_f\aprox1031.921J
Respuesta: 1031,921 julios
Frequently asked questions (FAQs)
What are the real solutions of the cubic equation x^3 - 4x^2 + 5x + 2 = 0?
+
Math Question: Solve the inequality: 2x + 5 < 15 for x.
+
Math question: What is the vertex of the parabola represented by the function 𝑦 = 2𝑥^2?
+
New questions in Mathematics