Question
A 50 kg box slides down an inclined plane 8.3 m long and 4 m high. If the friction force between the box and the inclined plane is 112 N, what is the work done by the friction force?
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Answer to a math question A 50 kg box slides down an inclined plane 8.3 m long and 4 m high. If the friction force between the box and the inclined plane is 112 N, what is the work done by the friction force?
Madelyn
4.787 Answers
Solución:
El trabajo realizado por la fuerza de fricción está dado por
W_f=fd
dónde
f es la fuerza de fricción entre el objeto y la superficie, y
d es la distancia recorrida por el objeto.
Según el teorema de Pitágoras, la distancia recorrida es
d=\sqrt{x^2+y^2}
d=\sqrt{8.3^2+4^2}
d\aproximadamente9.214m
Por tanto, el trabajo realizado es
W_f=112\cdot9.214
W_f\aprox1031.921J
Respuesta: 1031,921 julios
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