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A 50 kg box slides down an inclined plane 8.3 m long and 4 m high. If the friction force between the box and the inclined plane is 112 N, what is the work done by the friction force?

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Answer to a math question A 50 kg box slides down an inclined plane 8.3 m long and 4 m high. If the friction force between the box and the inclined plane is 112 N, what is the work done by the friction force?

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Madelyn

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Solución: El trabajo realizado por la fuerza de fricción está dado por W_f=fd dónde f es la fuerza de fricción entre el objeto y la superficie, y d es la distancia recorrida por el objeto. Según el teorema de Pitágoras, la distancia recorrida es d=\sqrt{x^2+y^2}

d=\sqrt{8.3^2+4^2}

d\aproximadamente9.214m Por tanto, el trabajo realizado es W_f=112\cdot9.214 W_f\aprox1031.921J Respuesta: 1031,921 julios

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A 50 kg box slides down an inclined plane 8.3 m long and 4 m high. If the friction force between the box and the inclined plane is 112 N, what is the work done by the friction force?

Answer to a math question A 50 kg box slides down an inclined plane 8.3 m long and 4 m high. If the friction force between the box and the inclined plane is 112 N, what is the work done by the friction force?

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