Buster’s dog house is 3 feet long, 2 feet wide, and 2 feet high. How much space would there be if Buster’s house was twice as long, twice as wide, and twice as high.

Solution:
1. Given original dimensions:
- Length: 3 feet
- Width: 2 feet
- Height: 2 feet

2. Calculate the original volume:
\text{Original Volume} = \text{Length} \times \text{Width} \times \text{Height} = 3 \times 2 \times 2 = 12 \, \text{cubic feet}

3. Double each dimension:
- New Length: 2 \times 3 = 6 \, \text{feet}
- New Width: 2 \times 2 = 4 \, \text{feet}
- New Height: 2 \times 2 = 4 \, \text{feet}

4. Calculate the new volume:
\text{New Volume} = \text{New Length} \times \text{New Width} \times \text{New Height} = 6 \times 4 \times 4 = 96 \, \text{cubic feet}