Question
David cuts a rope 60 m long into two pieces in the ratio 2:3. What is the length of the shorter piece of rope?
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Answer to a math question David cuts a rope 60 m long into two pieces in the ratio 2:3. What is the length of the shorter piece of rope?
Frederik
4.6103 Answers
1. Let the lengths of the two pieces of rope be represented as $2x$ and $3x$, since they are in the ratio 2:3.
2. According to the problem, the sum of the lengths of the two pieces is 60 m, so:
2x + 3x = 60
3. Combine like terms:
5x = 60
4. Solve for $x$:
x = \frac{60}{5}
x = 12
5. The length of the shorter piece of rope is $2x$, so:
2x = 2 \times 12
2x = 24
6. Therefore, the length of the shorter piece of rope is:
24 \, \text{m}
2. According to the problem, the sum of the lengths of the two pieces is 60 m, so:
3. Combine like terms:
4. Solve for $x$:
5. The length of the shorter piece of rope is $2x$, so:
6. Therefore, the length of the shorter piece of rope is:
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