1. Identify the slope of the given line y = 8x - 5. The slope is 8 since it's the coefficient of x.
2. Use the point-slope form of a line equation y - y_1 = m(x - x_1) where m is the slope and (x_1, y_1) is the point through which the line passes.
3. Point given is (-1, 8) and m = 8.
Substitute into the point-slope form:
y - 8 = 8(x + 1)
4. Distribute and solve for y:
y - 8 = 8x + 8
y = 8x + 16
5. Therefore, the equation of the line parallel to y = 8x - 5 passing through (-1, 8) is:
y = 8x + 16