Determine the x-intercept and y-intercepts: y = 2x^2 + 4x - 6

**X-Intercepts:**

y = 0

0 = 2x^2 + 4x - 6

Quadratic formula:
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Where:
a = 2
b = 4
c = -6

Discriminant calculation:
b^2 - 4ac = 16 + 48 = 64

Applying quadratic formula:

x = \frac{-4 \pm 8}{4}

Solutions:

x = 1 and
x = -3

**Y-Intercept:**

x = 0

y = 2 \cdot 0^2 + 4 \cdot 0 - 6 = -6

**Answers:**

X-Intercepts: (1, 0) and (-3, 0)
Y-Intercept: (0, -6)