Question
Determine the x-intercept and y-intercepts: y = 2x^2 + 4x - 6
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Answer to a math question Determine the x-intercept and y-intercepts: y = 2x^2 + 4x - 6
Birdie
4.5103 Answers
**X-Intercepts:**
y = 0
0 = 2x^2 + 4x - 6
Quadratic formula:
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
Where:
a = 2
b = 4
c = -6
Discriminant calculation:
b^2 - 4ac = 16 + 48 = 64
Applying quadratic formula:
x = \frac{-4 \pm 8}{4}
Solutions:
x = 1
x = -3
**Y-Intercept:**
x = 0
y = 2 \cdot 0^2 + 4 \cdot 0 - 6 = -6
**Answers:**
X-Intercepts: (1, 0) (-3, 0)
Y-Intercept: (0, -6)
Quadratic formula:
Where:
Discriminant calculation:
Applying quadratic formula:
Solutions:
**Y-Intercept:**
**Answers:**
X-Intercepts:
Y-Intercept:
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