If A = 6, B = 0, and the equation is A = (B-2)(C+5), then we can solve for C as follows:
**1. Substitute the values:**
Replace A, B, and the numeric values in the equation:
6 = (0 - 2)(C + 5)
**2. Simplify the expression:**
-2(C + 5) = 6
**3. Distribute the negative sign:**
-2C - 10 = 6
**4. Isolate C:**
-2C = 16
**5. Solve for C:**
C = **-8**
Therefore, if A = 6 and B = 0, then the value of C in the equation A = (B-2)(C+5) is **-8**.