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n 6 3n 5 5 n 1 2 n 7

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n+ 6 + 3n + 5 = - 5(n - 1) + 2(n - 7)

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Answer to a math question n+ 6 + 3n + 5 = - 5(n - 1) + 2(n - 7)

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104 Answers

$n+3n+6+5=-5(n-1)+2(n-7)$

$4n+6+5=-5(n-1)+2(n-7)$

$4n+11=-5(n-1)+2(n-7)$

$4n+11=-3n-9$

$4n=-3n-20$

$7n=-20$

$n=-\frac{20}{7}$

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(3b)⋅(5b^2)⋅(6b^3)