The second angle of a triangle is two times the first angle the third angle of the triangle is 92° more than the first angle find each angle of the triangle

1. Let the first angle be \( x \).

x

2. The second angle is two times the first angle.

2x

3. The third angle is 92° more than the first angle.

x + 92°

4. The sum of the angles in a triangle is 180°.

x + 2x + (x + 92°) = 180°

5. Simplify the equation.

4x + 92° = 180°

6. Solve for \( x \).

4x = 180° - 92°

4x = 88°

x = \frac{88°}{4}

x = 22°

7. Calculate the second angle.

2x = 2 \cdot 22° = 44°

8. Calculate the third angle.

x + 92° = 22° + 92° = 114°

The angles are:

22°, 44°, 114°