Question
write an equation of the line that passes through (7/10, 9/13) and is perpendicular to the X axis
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Answer to a math question write an equation of the line that passes through (7/10, 9/13) and is perpendicular to the X axis
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To find the equation of a line that is perpendicular to the x-axis and passes through the point (7/10, 9/13), we need to first determine the slope of the line.
Since the line is perpendicular to the x-axis, the slope of the line is undefined. This is because a line perpendicular to the x-axis has a slope of zero.
The equation of a line with slope 0 passing through a point (xβ, yβ) is given by:
y - yβ = 0(x - xβ)
Substituting the coordinates (7/10, 9/13) into the equation, we get:
y - 9/13 = 0(x - 7/10)
Simplifying further, we have:
y - 9/13 = 0
The equation of the line that passes through (7/10, 9/13) and is perpendicular to the x-axis is:
y = 9/13
Since the line is perpendicular to the x-axis, the slope of the line is undefined. This is because a line perpendicular to the x-axis has a slope of zero.
The equation of a line with slope 0 passing through a point (xβ, yβ) is given by:
y - yβ = 0(x - xβ)
Substituting the coordinates (7/10, 9/13) into the equation, we get:
y - 9/13 = 0(x - 7/10)
Simplifying further, we have:
y - 9/13 = 0
The equation of the line that passes through (7/10, 9/13) and is perpendicular to the x-axis is:
y = 9/13
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