Question
write an equation of the line that passes through (7/10, 9/13) and is perpendicular to the X axis
245
likes1224 views
Answer to a math question write an equation of the line that passes through (7/10, 9/13) and is perpendicular to the X axis
Miles
4.9114 Answers
To find the equation of a line that is perpendicular to the x-axis and passes through the point (7/10, 9/13), we need to first determine the slope of the line.
Since the line is perpendicular to the x-axis, the slope of the line is undefined. This is because a line perpendicular to the x-axis has a slope of zero.
The equation of a line with slope 0 passing through a point (x₁, y₁) is given by:
y - y₁ = 0(x - x₁)
Substituting the coordinates (7/10, 9/13) into the equation, we get:
y - 9/13 = 0(x - 7/10)
Simplifying further, we have:
y - 9/13 = 0
The equation of the line that passes through (7/10, 9/13) and is perpendicular to the x-axis is:
y = 9/13
Since the line is perpendicular to the x-axis, the slope of the line is undefined. This is because a line perpendicular to the x-axis has a slope of zero.
The equation of a line with slope 0 passing through a point (x₁, y₁) is given by:
y - y₁ = 0(x - x₁)
Substituting the coordinates (7/10, 9/13) into the equation, we get:
y - 9/13 = 0(x - 7/10)
Simplifying further, we have:
y - 9/13 = 0
The equation of the line that passes through (7/10, 9/13) and is perpendicular to the x-axis is:
y = 9/13
Frequently asked questions (FAQs)
Math question: What is the magnitude of the unit vector in the direction of vector with components ? (
+
What is the measure of an angle formed by the intersection of two lines, if the sum of its adjacent angles is 90 degrees?
+
Question: Solve the algebraic equation 4x + 7 = 23.
+
New questions in Mathematics