To calculate the number of different committees that can be formed, we will consider two cases:
Case 1: Committee with 0 women
Number of ways to choose 4 people with 0 women from 5 men = \binom{5}{4} = 5 ways
Case 2: Committee with 1 woman
Number of ways to choose 3 men and 1 woman from 4 women and 5 men = \binom{4}{1} \cdot \binom{5}{3} = 4 \cdot 10 = 40 ways
Total number of different committees that can be formed = Number of committees with 0 women + Number of committees with 1 woman = 5 + 40 = 45
\boxed{45} different committees can be formed.