solve p l s q 2 d 5 for p where pressure p back pressure in kilopascals length l 264 2615996 meters gas density s 1 135544
Question
solve
P = (L * S * Q^2)/D^5
for P
where
Pressure P = back pressure in kilopascals
Length L = 264.2615996 meters
Gas Density S = 1.135544434 kilograms/meter^3
Gas Flow Q = 5.663369322 meters^3/minute
Pipe Diameter D = 101.6 millimeters
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Answer to a math question solve
P = (L * S * Q^2)/D^5
for P
where
Pressure P = back pressure in kilopascals
Length L = 264.2615996 meters
Gas Density S = 1.135544434 kilograms/meter^3
Gas Flow Q = 5.663369322 meters^3/minute
Pipe Diameter D = 101.6 millimeters
Given the formula: P = \frac{L \cdot S \cdot Q^2}{D^5}
Substitute the given values: Length, L = 264.2615996 meters Gas density, S = 1.135544434 kilograms/meter ^3 Gas flow, Q = 5.663369322 meters ^3 /minute Pipe diameter, D = 101.6 millimeters = 0.1016 meters
Substitute these values into the formula: P = \frac{264.2615996 \times 1.135544434 \times (5.663369322)^2}{(0.1016)^5}
P = \frac{264.2615996 \times 1.135544434 \times 32.06274866}{0.000001629}
P\approx889036\text{ kPa}
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