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a 6x 5 x 20
Question
a) 6x − 5 > x + 20
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Answer to a math question a) 6x − 5 > x + 20
Murray
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Answers
$6x-5-x > 20$
$6x-x > 20+5$
$5x > 20+5$
$5x > 25$
$\begin{align*} & x>5 \\ & \begin{array}{l}x\in\langle5,+\infty\rangle \\ \end{array}\end{align*}$
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I have a complex function I would like to integrate over. I can use two approaches and they should give the same solution. If I want to find the contour integral ∫𝛾𝑧¯𝑑𝑧 for where 𝛾 is the circle |𝑧−𝑖|=3 oriented counterclockwise I get the following: ∫2𝜋0𝑖+3𝑒𝑖𝑡⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯𝑑(𝑖+3𝑒𝑖𝑡)=∫2𝜋03𝑖(−𝑖+3𝑒−𝑖𝑡)𝑒𝑖𝑡𝑑𝑡=18𝜋𝑖 If I directly apply the Residue Theorem, I would get ∫𝛾𝑧¯𝑑𝑧=2𝜋𝑖Res(𝑓,𝑧=0)=2𝜋𝑖
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a) 6x − 5 > x + 20
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