Se um ponto (x,y) estiver no segundo quadrante,
x < 0
y > 0
Assim, para o ponto P (m, 1 - 2m) estar no segundo quadrante
m < 0
1 - 2m > 0
1 > 2m
2m < 1
m < 1/2
Encontre a interseção:
m < 0 ∩ m < 1/2
Responder:
m < 0
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