Question

Find the equation of the line perpendicular to −5𝑥−3𝑦+5=0 passing through the point (0,−2)

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Madelyn

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28 Answers

Rearranging the equation: 3y=-5x+5 y=-\frac{5}{3}x+\frac{5}{3}
So slope here is -\frac{5}{3}
Since it is perpendicular, slope should be negative reciprocal: m_{perpendicular}=\frac{3}{5}
Equation as it passes through (0,-2): y-\left(-2\right)=\frac{3}{5}\left(x-0\right) y+2=\frac{3}{5}x

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