Rearranging the equation: 3y=-5x+5 y=-\frac{5}{3}x+\frac{5}{3}
So slope here is -\frac{5}{3}
Since it is perpendicular, slope should be negative reciprocal: m_{perpendicular}=\frac{3}{5}
Equation as it passes through (0,-2): y-\left(-2\right)=\frac{3}{5}\left(x-0\right) y+2=\frac{3}{5}x