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a company made 150 000 in the first year 145 000 in the second 140 000 in the third year successively during the first dec

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A company made 150,000 in the first year 145,000 in the second 140,000 in the third year successively during the first decade of this company's existence it made a total of

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Answer to a math question A company made 150,000 in the first year 145,000 in the second 140,000 in the third year successively during the first decade of this company's existence it made a total of

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Para calcular o total faturado pela empresa na primeira década de existência, precisamos somar os valores faturados em cada ano.

Ano 1: 150.000
Ano 2: 145.000
Ano 3: 140.000

Podemos observar que os valores estão diminuindo em uma progressão aritmética. Podemos então encontrar o valor faturado no décimo ano usando a fórmula da soma dos termos de uma progressão aritmética.

A fórmula para calcular a soma dos termos de uma progressão aritmética é:

S_n = (n/2) * (a_1 + a_n)

Onde:
S_n é a soma dos n termos
n é o número de termos
a_1 é o primeiro termo
a_n é o enésimo termo

Neste caso, n = 10, a_1 = 150.000 e a_n = 140.000. Substituindo na fórmula, temos:

S_10 = (10/2) * (150.000 + 140.000)
= 5 * (290.000)
= 1,450,000

Portanto, o faturamento total da empresa na primeira década de existência foi de 1,450,000 (em unidades monetárias).

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