initially we find slope (m)
m=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-1)}{4-2}= 0 $
since slope is 0 the equation will be equation of horizontal line which is y=y_1
Thus
y = -1
Frequently asked questions (FAQs)
What is the value of √(9 + √(16 + √(25 + √(36 + √(49 + √(64 + √(81 + √(100))))))))?
+
Math question: What is the turning point of the cubic function f(x) = x^3?