initially we find slope (m)
m=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-1)}{4-2}= 0 $
since slope is 0 the equation will be equation of horizontal line which is y=y_1
Thus
y = -1
Frequently asked questions (FAQs)
Find the real roots of the cubic equation 5x^3 - 2x^2 + 3x - 1 = 0.
+
What are the product and sum of two numbers if their product is 36 and their sum is 11?