initially we find slope (m)
m=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-1)}{4-2}= 0 $
since slope is 0 the equation will be equation of horizontal line which is y=y_1
Thus
y = -1
Frequently asked questions (FAQs)
What is the limit as x approaches 3 of (x^2 - 9) / (x - 3)
+
Math question: Evaluate log(base 5) of (2^3 * sqrt(125)) + log(base 4) of (16^2) - log(base 10) of 0.1