initially we find slope (m)
m=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-1)}{4-2}= 0 $
since slope is 0 the equation will be equation of horizontal line which is y=y_1
Thus
y = -1
Frequently asked questions (FAQs)
Math Question: Simplify the radical expression √(18)÷√(2).
+
Question: Find the limit of (3x^2 - 2)/(x + 1) as x approaches 2.
+
What is the integral of ∫(x^3 + 4x^2 + 2x - 9) dx using the standard formulas?