initially we find slope (m)
m=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-1)}{4-2}= 0 $
since slope is 0 the equation will be equation of horizontal line which is y=y_1
Thus
y = -1
Frequently asked questions (FAQs)
What is the value of f(3) when f(x) = 1/x?
+
Math Question: Find the absolute extrema of the function f(x) = x^3 - 6x^2 + 9x on the interval [0, 5].
+
What is the amplitude and period of the sine function f(x) = sin x? (