initially we find slope (m)
m=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-1)}{4-2}= 0 $
since slope is 0 the equation will be equation of horizontal line which is y=y_1
Thus
y = -1
Frequently asked questions (FAQs)
What is the slope of a line passing through the points (-3, 2) and (5, 7)?
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What is the value of f(x) = log(x) / ln(x)?
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What is the value of tangent in a right triangle given that the opposite side is 5 and the adjacent side is 12?