initially we find slope (m)
m=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-1)}{4-2}= 0 $
since slope is 0 the equation will be equation of horizontal line which is y=y_1
Thus
y = -1
Frequently asked questions (FAQs)
Question: What is the maximum value of the function f(x) = 2x^3 - 3x^2 + 4x - 6 on the interval [-1, 3]?
+
Math question: What is the radius of a circle if the equation of the circle's function is x^2 + y^2 = 16?