initially we find slope (m)
m=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-1)}{4-2}= 0 $
since slope is 0 the equation will be equation of horizontal line which is y=y_1
Thus
y = -1
Frequently asked questions (FAQs)
Question: What is the integral from 0 to 4 of (2x + 3) dx using the Fundamental Theorem of Calculus?
+
What is the value of x when f(x) = 1000 for the exponential function f(x) = 10^x, and what is the value of x when f(x) = 100 for the exponential function f(x) = e^x?
+
What is the quadratic formula for solving \(ax^2 + bx + c = 0\)?