initially we find slope (m)
m=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-1)}{4-2}= 0 $
since slope is 0 the equation will be equation of horizontal line which is y=y_1
Thus
y = -1
Frequently asked questions (FAQs)
What is the value of the tangent function at 45 degrees on the unit circle chart?
+
What is the limit of (3x^2 - x + 5)/(2x^2 + 4x - 3) as x approaches 2?
+
What is the measure of angle A in triangle ABC if angle B is 50°, angle C is 80°?