The number of permutations if all letters were distinct is
9P4=3024
B is repeated twice so we will divide it by 2!
\frac{3024}{2!}=1512
answer
1512
Frequently asked questions (FAQs)
Question: What is the product of (a+b)^2 when expanded using the binomial theorem?
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What is the integral of f(x) from a to b when f(x) = x^2 + 3x − 2? (
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