Question

Suppose that a device has been created that launches objects at ground level and that its operation is modeled by the function h(x) = -4×² + 256x, with h being the height (in meters) and x being the distance (in meters) What is the maximum height that the object reaches?

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Answer to a math question Suppose that a device has been created that launches objects at ground level and that its operation is modeled by the function h(x) = -4×² + 256x, with h being the height (in meters) and x being the distance (in meters) What is the maximum height that the object reaches?

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Miles

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114 Answers

h\left(x\right)=-4x^2+256x then h'(x) = -8x+256 For critical point; h'(x)=0 -8x+256=0 x=256/8=32 x=32 Now h''(x)=-8 which is less than 0, so the function give maximum value at x=32. So the maximum height = -4\times32^2+256\times32=\:4096

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Suppose that a device has been created that launches objects at ground level and that its operation is modeled by the function h(x) = -4×² + 256x, with h being the height (in meters) and x being the distance (in meters) What is the maximum height that the object reaches?

Answer to a math question Suppose that a device has been created that launches objects at ground level and that its operation is modeled by the function h(x) = -4×² + 256x, with h being the height (in meters) and x being the distance (in meters) What is the maximum height that the object reaches?

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