To find the equation of the line that passes through the points (18,22) and (54,26), we can use the slope-intercept form of a linear equation:
y = mx + b
where m is the slope of the line and b is the y-intercept.
Step 1: Find the slope (m)
The slope (m) of a line passing through two points (x1, y1) and (x2, y2) is given by the formula:
m = \frac{y2 - y1}{x2 - x1}
Using the points (18,22) and (54,26), we have:
m = \frac{26 - 22}{54 - 18}
m = \frac{4}{36}
m = \frac{1}{9}
Step 2: Find the y-intercept (b)
We can use the point-slope form of a linear equation to find b:
y - y1 = m(x - x1)
Using the point (18,22), we have:
y - 22 = \frac{1}{9}(x - 18)
y - 22 = \frac{1}{9}(x) - 2
y = \frac{1}{9}x + 20
Therefore, the equation of the line passing through the points (18,22) and (54,26) is:
y = \frac{1}{9}x + 20
To find the point whose abscissa is 9, we substitute x = 9 into the equation above:
y = \frac{1}{9}(9) + 20
y = 1 + 20
y = 21
Therefore, the point whose abscissa is 9 is (9,21).
Answer: The equation of the line is y = \frac{1}{9}x + 20 and the point with an abscissa of 9 is (9,21).