Question
A membership to the gym cost $25 per person in 1995. The membership cost has increased by an average $6 per person for each year since 1995. Write a linear equation for the cost of a gym membership for one person since 1995. What is the cost of a gym membership in 2009?
290
likes1450 views
Answer to a math question A membership to the gym cost $25 per person in 1995. The membership cost has increased by an average $6 per person for each year since 1995. Write a linear equation for the cost of a gym membership for one person since 1995. What is the cost of a gym membership in 2009?
Rasheed
4.755 Answers
To write a linear equation for the cost of a gym membership for one person since 1995, we can use the slope-intercept form of a linear equation: y = mx + b.
Let's break down the given information:
In 1995, the gym membership cost $25 per person. This gives us the y-intercept (b) of our equation, which is 25.
The membership cost has increased by an average of $6 per person for each year since 1995. This tells us the rate of change or the slope (m) of our equation, which is 6.
Putting this information together, we can write the linear equation for the cost of a gym membership for one person since 1995 as:
y = 6x + 25
Now, to find the cost of a gym membership in 2009, we need to determine the value of x, which represents the number of years since 1995.
Since 2009 is 14 years after 1995, we substitute x = 14 into our equation:
y = 6(14) + 25
y = 84 + 25
y = 109
Therefore, the cost of a gym membership in 2009 is $109.
Frequently asked questions (FAQs)
What is the probability of rolling a prime number on a fair 6-sided die?
+
Math Question: Find the limit as x approaches 0 of (e^x - x - 1) / (sin(2x) - 2x). Why would applying L'Hospital's Rule be helpful?
+
Find the maximum value of the function f(x) = 3sin(2x) + cos(x) on the interval [0, π].
+
New questions in Mathematics