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Find the vertex F(x)=x^2-10x

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Answer to a math question Find the vertex F(x)=x^2-10x

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Darrell
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91 Answers
f(x)=x^2-10x f(x)=x^2-10x+25-25 f(x)=(x-5)^2-25 Vertex:(5, -25)

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(3b)⋅(5b^2)⋅(6b^3)

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