Question

To verify that a 1 kg gold bar is actually made of pure gold, a dynamometer is used to record the weight of the bar submerged in water and out of water. a) What would be the value of the weight of the ingot recorded by the dynamometer out of the water? b) What magnitude of thrust does the ingot receive when it is submerged? c) What would the weight of the ingot have to be when it is submerged? Data Pagua = 1000 kg/m³ Pagua= 19300 kg/m³

105

likes524 views

Adonis

4.4

77 Answers

Solución:
a) W=mg W=1kg\cdot9.81m/s^2 W=98.1N
b) F_b=mg\frac{\rho_{fluido}}{\rho{objeto}} F_b=1kg\cdot9.81m/s^2\cdot\frac{1000kg/m^3}{ 19300kg/m^3} F_b=0.51N
c) W_{sumergido}=W-F_b W_{sumergido}=98.1N-0.51N W_{sumergido}=97.59N

Frequently asked questions (FAQs)

What conditions must be satisfied in order for two triangles to be considered congruent?

+

What are the characteristics of a hyperbola with a vertical major axis and a center at (0,0)?

+

What is the value of arccos(0.5) in radians?

+

New questions in Mathematics