Question

To verify that a 1 kg gold bar is actually made of pure gold, a dynamometer is used to record the weight of the bar submerged in water and out of water. a) What would be the value of the weight of the ingot recorded by the dynamometer out of the water? b) What magnitude of thrust does the ingot receive when it is submerged? c) What would the weight of the ingot have to be when it is submerged? Data Pagua = 1000 kg/m³ Pagua= 19300 kg/m³

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Adonis

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Solución:
a) W=mg W=1kg\cdot9.81m/s^2 W=98.1N
b) F_b=mg\frac{\rho_{fluido}}{\rho{objeto}} F_b=1kg\cdot9.81m/s^2\cdot\frac{1000kg/m^3}{ 19300kg/m^3} F_b=0.51N
c) W_{sumergido}=W-F_b W_{sumergido}=98.1N-0.51N W_{sumergido}=97.59N

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