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string x 5 int y 2 system out println x y
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String x = 5 Int y=2 System.out.println(x+y)
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Answer to a math question String x = 5 Int y=2 System.out.println(x+y)
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Since the string x = 5 can be converted into numerical value, (x + y) = (5 + 2) = 7
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I have a complex function I would like to integrate over. I can use two approaches and they should give the same solution. If I want to find the contour integral β«πΎπ§Β―ππ§ for where πΎ is the circle |π§βπ|=3 oriented counterclockwise I get the following: β«2π0π+3πππ‘β―β―β―β―β―β―β―β―β―β―β―β―β―β―β―β―β―π(π+3πππ‘)=β«2π03π(βπ+3πβππ‘)πππ‘ππ‘=18ππ If I directly apply the Residue Theorem, I would get β«πΎπ§Β―ππ§=2ππRes(π,π§=0)=2ππ
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I have a complex function I would like to integrate over. I can use two approaches and they should give the same solution. If I want to find the contour integral β«πΎπ§Β―ππ§ for where πΎ is the circle |π§βπ|=3 oriented counterclockwise I get the following: β«2π0π+3πππ‘β―β―β―β―β―β―β―β―β―β―β―β―β―β―β―β―β―π(π+3πππ‘)=β«2π03π(βπ+3πβππ‘)πππ‘ππ‘=18ππ If I directly apply the Residue Theorem, I would get β«πΎπ§Β―ππ§=2ππRes(π,π§=0)=2ππ
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