Question

What is the percentage of nitrogen abundance in copper dinatrate Cu(NO3)2

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Fred

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48 Answers

utilizar masas atómicas como
Cu = 63,5
norte = 14
O = 16
masa de una molécula de dinitrato de cobre
= 63,5 + 2 x (14 + 3 x 16) = 63,5 + 2 x (14 + 48) = 63,5 + 2 x 62 = 187,5 uma
masa de nitrógeno en una molécula de dinitrato de cobre = 2 x 14 = 28 uma
porcentaje
=\frac{100\times28}{187.5}\aprox14.93\%

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