the equation of the circle that passes through 5 3 and is tangent to the abscissa axis at x 2 is a x 2 2 y 3 2 9 b x 2 2 y
Question
The equation of the circle that passes through (5,3) and is tangent to the abscissa axis at x=2 is
a.(x-2)^2 (y 3)^2 = 9
b.(x-2)^2 (y-3)^2 = 9
c.(x-2)^2 (y-3)^2 = 4
d.(x-2)^2 (y 1)^2 = 4
e.(x-2)^2 (y-1)^2 = 4
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Answer to a math question The equation of the circle that passes through (5,3) and is tangent to the abscissa axis at x=2 is
a.(x-2)^2 (y 3)^2 = 9
b.(x-2)^2 (y-3)^2 = 9
c.(x-2)^2 (y-3)^2 = 4
d.(x-2)^2 (y 1)^2 = 4
e.(x-2)^2 (y-1)^2 = 4
What is the equation of the hyperbola with center at (2, -3), vertical transverse axis, vertices at (2, -1) and (2, -5), and foci at (2, 0) and (2, -6)?
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