How much does 7.2 moles of ammonium dichromate weigh? (NH4)2Cr2O7



Answer to a math question How much does 7.2 moles of ammonium dichromate weigh? (NH4)2Cr2O7

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Para calcular el peso de 7.2 moles de dicromato de amonio, necesitamos conocer la masa molar de dicha sustancia.

La fórmula química del dicromato de amonio es (NH4)2Cr2O7. Para calcular la masa molar, debemos sumar las masas atómicas de cada elemento multiplicadas por su respectivo subíndice.

La masa atómica del nitrógeno (N) es aproximadamente 14.01 g/mol, la del hidrógeno (H) es aproximadamente 1.01 g/mol, la del cromo (Cr) es aproximadamente 52.00 g/mol, y la del oxígeno (O) es aproximadamente 16.00 g/mol.

Por lo tanto, podemos calcular la masa molar del dicromato de amonio de la siguiente manera:

Masa molar = (2 * masa del nitrógeno) + (8 * masa del hidrógeno) + (2 * masa del cromo) + (7 * masa del oxígeno)

Masa molar = (2 * 14.01 g/mol) + (8 * 1.01 g/mol) + (2 * 52.00 g/mol) + (7 * 16.00 g/mol)

Masa molar = 28.02 g/mol + 8.08 g/mol + 104.00 g/mol + 112.00 g/mol

Masa molar = 252.10 g/mol

Ahora que tenemos la masa molar del dicromato de amonio, podemos calcular el peso de 7.2 moles multiplicando la masa molar por el número de moles:

Peso = 7.2 moles * 252.10 g/mol

Peso = 1813.92 g

Por lo tanto, 7.2 moles de dicromato de amonio pesan 1813.92 gramos.

\textbf{Answer:} El peso de 7.2 moles de dicromato de amonio es de 1813.92 gramos.

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