Question

Consider numbers from 1 to 2023. We want to delete 3 consecutive, so that the avarage of the left numbers is a whole number. How do we do that

97

likes487 views

Madelyn

4.7

28 Answers

Determine the average of the range 1 to 2023. The sum of consecutive integers from 1 to N is given by the formula: sum = (N/2) x (first number + last number). In this case, N = 2023, and the first number is 1, and the last number is 2023. So the sum is (2023/2) (1 + 2023) = 2,047,276.
Since the average of the remaining numbers needs to be a whole number, the sum of the remaining numbers must be divisible by the number of remaining numbers.
The average of the three numbers to be removed must be whole numbers:
\frac{(x+x+1+x+2)}{3} = 2023
3x + 3 = 3(2023)
3x = 6066
x = 2022
x is the first number the numbers are:
2022, 2023, 1

Frequently asked questions (FAQs)

What is the mixed number representation of 6 and 3/4 - 2 and 1/2? Factoring numbers, find the prime factors of 96. Real numbers: Is √61 a rational or irrational number?

+

What is the equation of the line passing through (1, 4) and (5, 10)?

+

What are the x-intercepts of the graph y = 2x² + 3x - 4?

+

New questions in Mathematics