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# A force of 750 pounds compresses a spring 3 inches from its natural length, which is 15 inches. What will be the work done to compress it 3 inches more?

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## Answer to a math question A force of 750 pounds compresses a spring 3 inches from its natural length, which is 15 inches. What will be the work done to compress it 3 inches more?

Jett
4.7
To determine the work done to compress the spring an additional 3 inches, we can utilize the formula for the elastic potential energy of a spring: U = 1/2 * k * x^2 where: U is the elastic potential energy $in inch-pounds$ k is the spring constant $in pounds per inch$ x is the compression or extension of the spring $in inches$ We know that a force of 750 pounds compresses the spring 3 inches, so we can deduce the spring constant: 750 pounds = k * 3 inches k = 250 pounds per inch Now, let's calculate the work done to compress the spring an additional 3 inches $from 3 inches to 6 inches$: U = 1/2 * 250 pounds per inch * $3 inches$^2 U = 1125 inch-pounds Therefore, the work done to compress the spring an additional 3 inches is 1125 inch-pounds.
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