Question

A,B,C and D are the corners of a rectangular building. Find the lengths the diagonals if AB measures 38' - 9" and AD measures 56' - 3"

99

likes496 views

Jayne

4.4

73 Answers

Answer:
AB = 38'9" = 465"
AD = 56'3" = 675"
By Pythagoras theorem,
AB^2+AD^2=AC^2
\left(465\right)^2+\left(675\right)^2=AC^2
671850=AC^2
\therefore AC=819.6"
Diagonals = 68' 3.6"

Frequently asked questions (FAQs)

Math question: Find the angle in degrees for which sinθ = 0.5.

+

What is the maximum value of the parabola function y = 2x² - 3x + 5?

+

Question: In triangle ABC, if angle A is equal to angle B, and side AB is congruent to side BC, what can we conclude about the triangle?

+

New questions in Mathematics