Question
A,B,C and D are the corners of a rectangular building. Find the lengths the diagonals if AB measures 38' - 9" and AD measures 56' - 3"
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Answer to a math question A,B,C and D are the corners of a rectangular building. Find the lengths the diagonals if AB measures 38' - 9" and AD measures 56' - 3"
Jayne
4.474 Answers
Answer:
AB = 38'9" = 465"
AD = 56'3" = 675"
By Pythagoras theorem,
AB^2+AD^2=AC^2
\left(465\right)^2+\left(675\right)^2=AC^2
671850=AC^2
\therefore AC=819.6"
Diagonals = 68' 3.6"
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