A,B,C and D are the corners of a rectangular building. Find the lengths the diagonals if AB measures 38' - 9" and AD measures 56' - 3"

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Answer to a math question A,B,C and D are the corners of a rectangular building. Find the lengths the diagonals if AB measures 38' - 9" and AD measures 56' - 3"

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Jayne

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Answer: AB = 38'9" = 465" AD = 56'3" = 675" By Pythagoras theorem, AB^2+AD^2=AC^2

\left(465\right)^2+\left(675\right)^2=AC^2

671850=AC^2

\therefore AC=819.6" Diagonals = 68' 3.6"

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