64-6x^2>0

Name: Solved: 64-6x^2>0 - MathMaster
Brand: MathMaster
Rating: 4.9 (300 reviews)

300

likes

1498 views

Answer to a math question 64-6x^2>0

$Expert avatar$

Tiffany

4.5

103 Answers

$-6{x}^{2} > -64$

${x}^{2} < \frac{ 32 }{ 3 }$

$|x| < \sqrt{ \frac{ 32 }{ 3 } }$

$|x| < \frac{ \sqrt{ 32 } }{ \sqrt{ 3 } }$

$|x| < \frac{ {2}^{2}\sqrt{ 2 } }{ \sqrt{ 3 } }$

$|x| < \frac{ 4\sqrt{ 2 } }{ \sqrt{ 3 } }$

$|x| < \frac{ 4\sqrt{ 6 } }{ 3 }$

$\begin{array} { l }\begin{array} { l }x < \frac{ 4\sqrt{ 6 } }{ 3 },& x \geq 0\end{array},\\\begin{array} { l }-x < \frac{ 4\sqrt{ 6 } }{ 3 },& x < 0\end{array}\end{array}$

$\begin{array} { l }x \in \left[ 0, \frac{ 4\sqrt{ 6 } }{ 3 }\right\rangle,\\\begin{array} { l }-x < \frac{ 4\sqrt{ 6 } }{ 3 },& x < 0\end{array}\end{array}$

$\begin{array} { l }x \in \left[ 0, \frac{ 4\sqrt{ 6 } }{ 3 }\right\rangle,\\\begin{array} { l }x > -\frac{ 4\sqrt{ 6 } }{ 3 },& x < 0\end{array}\end{array}$

$\begin{array} { l }x \in \left[ 0, \frac{ 4\sqrt{ 6 } }{ 3 }\right\rangle,\\x \in \langle-\frac{ 4\sqrt{ 6 } }{ 3 }, 0\rangle\end{array}$

$\begin{align*} & x\in\langle-\frac{ 4\sqrt{ 6 } }{ 3 },\frac{ 4\sqrt{ 6 } }{ 3 }\rangle \\ & \end{align*}$

Frequently asked questions (FAQs)

What is the unit vector component of vector V = (-3, 4) in the direction of vector U = (2, 1)?

Math question: In a triangle with side lengths a = 8, b = 12, and angle C = 60°, find the length of side c using the Sine Law.

What is the value of the hypotenuse (c) if the lengths of the other two sides (a and b) of a right triangle are 4 and 7, respectively?

New questions in Mathematics

1/2x +3 <4x-7

If O(3,-2) is reflected across x = 2. What are the coordinates of O

X^2 = 25

Determine the equations of the recipes that pass through the following pairs of points P1 (2;-1) and p2 (4;-1)

[(36,000,000)(0.000003)^2]divided(0.00000006)