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given cos26 k find cos13
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given cos26=k find cos13
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Answer to a math question given cos26=k find cos13
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cos(2θ) = 2 \times cos^2(θ) - 1
cos^2(θ) = \frac{(cos(2θ) +1)}{2}
cos^2(13) = \frac {cos(26) +1}{2}
cos^2(13) = \frac{k +1}{2}
\cos\:13\:=\pm\sqrt{\left(\frac{k+1}{2}\right)}}
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(3b)⋅(5b^2)⋅(6b^3)
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