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3 2b2
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3%2B2
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Answer to a math question 3%2B2
Hermann
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Respuesta%3A+%24%24+3%2B2%3D%5Cleft%281%2B1%2B1%5Cright%29%2B%5Cleft%281%2B1%5Cright%29%3D5+%24%24
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I have a complex function I would like to integrate over. I can use two approaches and they should give the same solution. If I want to find the contour integral β«πΎπ§Β―ππ§ for where πΎ is the circle |π§βπ|=3 oriented counterclockwise I get the following: β«2π0π+3πππ‘β―β―β―β―β―β―β―β―β―β―β―β―β―β―β―β―β―π(π+3πππ‘)=β«2π03π(βπ+3πβππ‘)πππ‘ππ‘=18ππ If I directly apply the Residue Theorem, I would get β«πΎπ§Β―ππ§=2ππRes(π,π§=0)=2ππ
5 1/9 + 2 2/3
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