Calculate the change in internal energy of a gas that receives 16000 J of heat at constant pressure (1.3 atm) expanding from 0.100 m3 to 0.200 m3. Question 1Answer to. 7050J b. 2125J c. None of the above d. 2828J and. 10295 J

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Answer to a math question Calculate the change in internal energy of a gas that receives 16000 J of heat at constant pressure (1.3 atm) expanding from 0.100 m3 to 0.200 m3. Question 1Answer to. 7050J b. 2125J c. None of the above d. 2828J and. 10295 J

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Solución: De la primera ley de la termodinámica, el cambio en la energía interna de un gas viene dado por \Delta U=Q+W donde Q es la energía agregada al gas al calentarlo, y W es el trabajo realizado sobre el gas , dado por W=-P\Delta V donde P es la presión del gas y V es el cambio de volumen del gas a medida que se realizaba el trabajo. Convirtiendo la presión de la atmósfera a Pascal, P=1.3atm\cdot\frac{101325Pa}{1atm} P=1317235Pa Sustituyendo los valores, \Delta U=16000-1317235\left(0.200 -0.100\derecha) \Delta U\aprox2828J Respuesta: Opción d

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