Question

Exercise 1 An ejidal association wishes to determine the distribution for the three different crops that it can plant for the next season on its available 900 hectares. Information on the total available and how many resources are required for each hectare of cultivation is shown in the following tables: Total available resource Water 15,000 m3 Fertilizer 5,000 kg Labor 125 day laborers Requirements per cultivated hectare Corn Soybeans Wheat Water 15 25 20 Fertilizer 5 8 7 Labor** 1/8 1/5 1/4 *The data in fraction means that with one day laborer it will be possible to care for 8, 5 and 4 hectares respectively. * Sales of crops 1 and 3, according to information from the Department of Agriculture, are guaranteed and exceed the capacity of the cooperative. However, soybeans must be limited to a maximum of 150 hectares. On the other hand, the profits for each hectare of crop obtained are estimated at: $7,500 for corn, $8,500 for soybeans and $8,000 for wheat. The objectives are to determine: • How many hectares of each crop must be allocated so that the profit is maximum. R= • The estimated profits for the ejidal cooperative in the next growing season. R=

255

likes
1273 views

Answer to a math question Exercise 1 An ejidal association wishes to determine the distribution for the three different crops that it can plant for the next season on its available 900 hectares. Information on the total available and how many resources are required for each hectare of cultivation is shown in the following tables: Total available resource Water 15,000 m3 Fertilizer 5,000 kg Labor 125 day laborers Requirements per cultivated hectare Corn Soybeans Wheat Water 15 25 20 Fertilizer 5 8 7 Labor** 1/8 1/5 1/4 *The data in fraction means that with one day laborer it will be possible to care for 8, 5 and 4 hectares respectively. * Sales of crops 1 and 3, according to information from the Department of Agriculture, are guaranteed and exceed the capacity of the cooperative. However, soybeans must be limited to a maximum of 150 hectares. On the other hand, the profits for each hectare of crop obtained are estimated at: $7,500 for corn, $8,500 for soybeans and $8,000 for wheat. The objectives are to determine: • How many hectares of each crop must be allocated so that the profit is maximum. R= • The estimated profits for the ejidal cooperative in the next growing season. R=

Expert avatar
Murray
4.5
92 Answers
To maximize profit, the ejidal association needs to allocate the hectares for each crop based on the available resources and constraints. Let's denote: x as the hectares of corn, y as the hectares of soybeans, and z as the hectares of wheat. The objective is to maximize the total profit: Total Profit = 7500x + 8500y + 8000z Subject to the following constraints: Land Availability Constraint: x + y + z ≤ 900 Resource Constraints: Water: 15x + 25y + 20z ≤ 15000 Fertilizer: 5x + 8y + 7z ≤ 5000 Labor: ​x/8 + y/5 + x/4 ≤ 125 Soybean Constraint (limited to a maximum of 150 hectares): y≤150 Using linear programming, we can solve these equations to find the optimal allocation for maximum profit. Here are the calculations: Maximize: 7500x + 8500y + 8000z Subject to: x + y + z <= 900 15x + 25y + 20z <= 15000 5x + 8y + 7z <= 5000 x/8 + y/5 + z/4 <= 125 y <= 150 The optimal allocation for maximum profit is: x=300 hectares of corn y=150 hectares of soybeans z=450 hectares of wheat The estimated profits for the ejidal cooperative in the next growing season would be: Profit=7500×300+8500×150+8000×450 = $6,225,000

Frequently asked questions (FAQs)
Question: What is the derivative of ∫[a to x] f(t) dt, where f(x) = 3x^2 - 2x + 1 and a is a constant? (
+
Question: What is the limit of (4x² + 2x + 3) / (x² + 5x) as x approaches infinity?
+
Question: What is 3/4 of 80 expressed as a decimal?
+
New questions in Mathematics
Find an arc length parameterization of the curve that has the same orientation as the given curve and for which the reference point corresponds to t=0. Use an arc length s as a parameter. r(t) = 3(e^t) cos (t)i + 3(e^t)sin(t)j; 0<=t<=(3.14/2)
12-6x=4x+2
Karina has a plot of 5,000 square meters in which she has decided that 60% of it will be used to plant vegetables. Of this part, 12% will be dedicated to planting lettuce. How much surface area of the plot will be used for cultivation?
How many percent is one second out a 24 hour?
In a random sample of 600 families in the Metropolitan Region that have cable television service, it is found that 460 are subscribed to the Soccer Channel (CDF). How large a sample is required to be if we want to be 95% confident that the estimate of “p” is within 0.03?
Determine the correct value: A company knows that invoices pending collection have a normal distribution with a mean of $1.65 million, with a standard deviation of $0.2 million, then: The probability that an invoice pending collection has an amount that is within more than 2 deviations below the mean, is:
What payment 7 months from now would be equivalent in value to a $3,300 payment due 23 months from now? The value of money is 2.7% simple interest. Round your answer to 2 decimal places. Show all work and how you arrive at the answer..
I need .23 turned into a fraction
B - (-4)=10
4X^2 25
The expected market return is 13,86% and the risk free rate 1%. What would then be the risk premium on the common stocks of a company which beta is 1,55? (in %, 2 decimal places)
Perpetual annuities are a series of payments whose duration has no end. Explain how can we calculate them, if they have no end?
The ninth term of a given geometric progression, with reason q , is 1792, and its fourth term is 56. Thus, calculate the fourth term of another geometric progression, whose ratio is q +1 and whose first term is equal to the first term of the first P.G. described.
Your boss asks you to plan the sample size for a randomized, double-blind, controlled trial in the clinical development of a cure for irritable bowl disease. Current standard treatment shall be compared with a new treatment in this trial. The S3-guideline of AWM demonstrated a mean change of the summary score of the validated health related quality of life questionnaire at 8 weeks of 16 with standard deviation 23 under standard treatment. You quote the drop-out rate of 11% from literature (previous phase of clinical development). Your research yielded a clinically important effect of 4 that has been found to be the Minimal Clinically Important Difference (MCID). In order to demonstrate superiority of the new treatment over standard of care, you assume that the change in of the summary score of the validated health related quality of life questionnaire follows a normal distribution, and that the standard deviation is the same for both treatments. How many patientes would one need to recruit for the trial to demonstrate the clinically interesting difference between treatments at significance level 5% with 95% power?
I. Order to add 40.25+1.31+.45 what is the first action to do ?
Engineers want to design seats in commercial aircraft so that they are wide enough to fit ​95% of all males.​ (Accommodating 100% of males would require very wide seats that would be much too​ expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.2 in. Find P95. That​ is, find the hip breadth for men that separates the smallest ​95% from the largest 5​%.
For what values of m is point P (m, 1 - 2m) in the 2⁰ quadrant?
factor the polynomial completely over the set of complex numbers b(x)=x^4-2x^3-17x^2+4x+30
simplify w+[6+(-5)]
Sin(5pi/3)