\frac{2}{3}+\frac{5}{6}\times\frac{1}{2}=\:\frac{2}{3}+\frac{5}{12}=\frac{\left(2\times4\right)}{\left(3\times4\right)}+\frac{5}{12}=\frac{8}{12}+\frac{5}{12}=\frac{13}{12}
or 1\frac{1}{12}
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Question: What is the value of the derivative of f(x) = 2x^3 - 5x^2 + 4x - 7 at x = 2?
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What is the value of f(-2) in the cubic function f(x) = x^3?