\frac{2}{3}+\frac{5}{6}\times\frac{1}{2}=\:\frac{2}{3}+\frac{5}{12}=\frac{\left(2\times4\right)}{\left(3\times4\right)}+\frac{5}{12}=\frac{8}{12}+\frac{5}{12}=\frac{13}{12}
or 1\frac{1}{12}
Frequently asked questions (FAQs)
What is the limit of (2x+3)/(x^2+1) as x approaches 5?
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Question: What is the integral of the function f(x) = 2x^3 + 4x^2 - 5x + 3 with respect to x, over the interval [0, 4]?
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What is the limit as x approaches 2 of (3x^2 - 7x + 1)?