\frac{2}{3}+\frac{5}{6}\times\frac{1}{2}=\:\frac{2}{3}+\frac{5}{12}=\frac{\left(2\times4\right)}{\left(3\times4\right)}+\frac{5}{12}=\frac{8}{12}+\frac{5}{12}=\frac{13}{12}
or 1\frac{1}{12}
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Math question: Find the absolute extrema of the function f(x) = x^3 - 6x^2 + 9x on the closed interval [0,5].