\frac{2}{3}+\frac{5}{6}\times\frac{1}{2}=\:\frac{2}{3}+\frac{5}{12}=\frac{\left(2\times4\right)}{\left(3\times4\right)}+\frac{5}{12}=\frac{8}{12}+\frac{5}{12}=\frac{13}{12}
or 1\frac{1}{12}
Frequently asked questions (FAQs)
Math question: Using the limit laws, find the limit as x approaches 2 of (3x^2 + 4x - 9).
+
What is the value of the hypotenuse in a right triangle with an opposite side of 12 and an adjacent side of 5?
+
What values of x satisfy the equation √(3x - 4) = 7?