Loading [MathJax]/jax/element/mml/optable/GeneralPunctuation.js
^x+1 +1 describe transformation","","Solution:\u003Cbr />\n1. Given function:\u003Cbr />\n * \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>y = -24^{x+1} + 1\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Base function:\u003Cbr />\n * \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>y = 4^x\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Identify transformations step-by-step:\u003Cbr />\n - **Translation horizontally**: The function has \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x+1\u003C/math-field>\u003C/math-field> as the exponent instead of \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field>. This indicates a horizontal shift to the left by 1 unit.\u003Cbr />\n - **Vertical stretch and reflection**: The coefficient before \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>4\u003C/math-field>\u003C/math-field> is \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>-2\u003C/math-field>\u003C/math-field>.\u003Cbr />\n - **Vertical stretch**: The factor \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>2\u003C/math-field>\u003C/math-field> indicates that the function is stretched vertically by a factor of \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>2\u003C/math-field>\u003C/math-field>.\u003Cbr />\n - **Reflection**: The negative sign indicates a reflection across the x-axis.\u003Cbr />\n - **Vertical translation**: The \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>+1\u003C/math-field>\u003C/math-field> outside the function indicates a vertical shift upwards by 1 unit.\u003Cbr />\n\u003Cbr />\n4. Describe the complete transformation:\u003Cbr />\n - The function \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>y = 4^x\u003C/math-field>\u003C/math-field> undergoes the following transformations: a horizontal shift to the left by 1 unit, a vertical stretch by a factor of 2, reflection across the x-axis, and finally a vertical shift upwards by 1 unit.",1255,251,"y-2-4-x-1-1-describe-transformation",{"id":44,"category":36,"text_question":45,"photo_question":38,"text_answer":46,"step_text_answer":8,"step_photo_answer":8,"views":47,"likes":48,"slug":49},538086,"Add the polynomials gx=x3-2x2+3x-1+4x2-x+2","Solution: \u003Cbr />\n1. Write down the given polynomials:\u003Cbr />\n- First polynomial: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>gx = x^3 - 2x^2 + 3x - 1\u003C/math-field>\u003C/math-field>\u003Cbr />\n- Second polynomial: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>4x^2 - x + 2\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Align and add the polynomials term by term:\u003Cbr />\n- \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>gx = x^3 - 2x^2 + 3x - 1\u003C/math-field>\u003C/math-field>\u003Cbr />\n- \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>4x^2 - x + 2\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Add the corresponding like terms:\u003Cbr />\n- For \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x^3\u003C/math-field>\u003C/math-field> terms: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x^3\u003C/math-field>\u003C/math-field>\u003Cbr />\n- For \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x^2\u003C/math-field>\u003C/math-field> terms: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>-2x^2 + 4x^2 = 2x^2\u003C/math-field>\u003C/math-field>\u003Cbr />\n- For \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field> terms: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>3x - x = 2x\u003C/math-field>\u003C/math-field>\u003Cbr />\n- For constant terms: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>-1 + 2 = 1\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. The resulting polynomial after addition is:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x^3 + 2x^2 + 2x + 1\u003C/math-field>\u003C/math-field>",739,148,"add-the-polynomials-g-x-x3-2x2-3x-1-4x2-x-2",{"id":51,"category":36,"text_question":52,"photo_question":38,"text_answer":53,"step_text_answer":8,"step_photo_answer":8,"views":54,"likes":55,"slug":56},538085,"R=3m. Calculate the volume of the sphere. Round to the nearest tenth if necessary","1. The formula for the volume of a sphere is \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi R^3 \u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>2. Substitute the given radius \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> R = 3 \\, \\text{m} \u003C/math-field>\u003C/math-field> into the formula:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi 3^3 \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>3. Calculate \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> 3^3 = 27 \u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>4. Thus, the volume becomes:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi \\times 27 \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>5. Simplify the expression:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4 \\times 27}{3} \\pi = 36 \\pi \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>6. Use the approximation \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\pi \\approx 3.1416 \u003C/math-field>\u003C/math-field> :\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V \\approx 36 \\times 3.1416 \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>7. Calculate the approximate volume:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V\\approx113.0973\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>8. Round to the nearest tenth:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V \\approx 113.1 \\, \\text{m}^3 \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>Therefore, the volume of the sphere is approximately \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> 113.1 \\, \\text{m}^3 \u003C/math-field>\u003C/math-field> .",1203,241,"r-3m-calculate-the-volume-of-the-sphere-round-to-the-nearest-tenth-if-necessary",{"id":58,"category":36,"text_question":59,"photo_question":38,"text_answer":60,"step_text_answer":8,"step_photo_answer":8,"views":61,"likes":62,"slug":63},538084,"Width of 12 in. Calculate the volume of the sphere. Round to the nearest tenth if necessary","1. Identify the radius of the sphere. Given the width is 12 inches, the diameter is 12 inches. Therefore, the radius is half of the diameter:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> r = \\frac{12}{2} = 6 \\, \\text{in} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Use the formula for the volume of a sphere:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi r^3 \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Substitute the radius into the formula:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi 6^3 \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. Calculate:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi \\times 216 = \\frac{864}{3} \\pi = 288 \\pi \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n5. Approximate using \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\pi \\approx 3.1416 \u003C/math-field>\u003C/math-field>:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V \\approx 288 \\times 3.1416 = 904.8 \\, \\text{in}^3 \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n6. The volume of the sphere, rounded to the nearest tenth, is approximately:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> 904.8 \\, \\text{in}^3 \u003C/math-field>\u003C/math-field>",278,56,"width-of-12-in-calculate-the-volume-of-the-sphere-round-to-the-nearest-tenth-if-necessary",{"id":65,"category":36,"text_question":66,"photo_question":38,"text_answer":67,"step_text_answer":8,"step_photo_answer":8,"views":68,"likes":69,"slug":70},538083,"Calculate the volume tothenearesttenthofacubiccentimeter of a golf ball whose diameter is 4.267cm","1. The formula for the volume of a sphere is given by \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V = \\frac{4}{3} \\pi r^3\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>2. The diameter of the golf ball is given as 4.267 cm, so the radius is half of that: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>r = \\frac{4.267}{2} = 2.1335 \\, \\text{cm}\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>3. Substitute the radius into the volume formula: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V = \\frac{4}{3} \\pi 2.1335^3\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>4. Calculate the cube of the radius: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>2.1335^3 = 9.707432537375\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>5. Substitute this back into the formula: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V=\\frac{4}{3}\\pi\\times9.707432537375\\approx40.7\\,\\text{cm}^3\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>6. The volume of the golf ball is approximately \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>40.7\\,\\text{cm}^3\u003C/math-field>\u003C/math-field> .",1440,288,"calculate-the-volume-to-the-nearest-tenth-of-a-cubic-centimeter-of-a-golf-ball-whose-diameter-is-4-267cm",{"id":72,"category":36,"text_question":73,"photo_question":38,"text_answer":74,"step_text_answer":8,"step_photo_answer":8,"views":75,"likes":76,"slug":77},538082,"Find the length of each base edge tothenearesttenthofameter of the 24m tall glass square pyramids of the Muttart Conservatory in Alberta, Canada, if each contains 5280m^3 of space","1. Volume V of a square pyramid is given by the formula:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V = \\frac{1}{3} B h\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>where B is the area of the base and h is the height of the pyramid.\u003Cbr>\u003Cbr>2. Given that the height h = 24 m and the volume V = 5280 m^3.\u003Cbr>\u003Cbr>3. The base is square, so if the side length of the base is s, then:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>B = s^2\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>4. Substituting into the volume formula:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>5280 = \\frac{1}{3} s^2 \\times 24\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>5. Simplify and solve for s^2:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>5280 = 8 s^2\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>s^2 = \\frac{5280}{8} = 660\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>6. Solve for s:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>s = \\sqrt{660} \\approx 25.7\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>7. To find the length of each base edge to the nearest tenth of a meter, compute:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>s \\approx 25.7 \\, \\text{m}\u003C/math-field>\u003C/math-field>",418,84,"find-the-length-of-each-base-edge-to-the-nearest-tenth-of-a-meter-of-the-24m-tall-glass-square-pyramids-of-the-muttart-conservatory-in-alberta-canada-if-each-contains-5280m-3-of-space",{"id":79,"category":36,"text_question":80,"photo_question":38,"text_answer":81,"step_text_answer":8,"step_photo_answer":8,"views":82,"likes":83,"slug":84},538081,"An observer is 150 meters away\n distance of a hot air balloon online\n straight line at ground level. From your position,\n measures an elevation angle of 40Β° up to\n the base of the balloon. At what height is\n find the hot air balloon?","Solution:\u003Cbr />\n1. Dado:\u003Cbr />\n- Distancia horizontal desde el observador hasta la base del globo: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>d = 150 \\ m\u003C/math-field>\u003C/math-field>\u003Cbr />\n- Ángulo de elevaciΓ³n: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\theta = 40^{\\circ}\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Usamos la funciΓ³n tangente para encontrar la altura \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>h\u003C/math-field>\u003C/math-field> del globo aerostΓ‘tico. La tangente de un Γ‘ngulo en un triΓ‘ngulo rectΓ‘ngulo es la razΓ³n entre la altura y la distancia horizontal:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\tantheta = \\frac{h}{d}\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Sustituimos los valores conocidos en la ecuaciΓ³n:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\tan40circ = \\frac{h}{150}\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. Resolvemos para \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>h\u003C/math-field>\u003C/math-field>:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>h = 150 \\times \\tan40circ\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n5. Calculamos el valor numΓ©rico:\u003Cbr />\n* Usando una calculadora, \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\tan40circ \\approx 0.8391\u003C/math-field>\u003C/math-field>\u003Cbr />\n* Entonces: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>h \\approx 150 \\times 0.8391 = 125.865 \\ m\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\nLa altura del globo aerostΓ‘tico es aproximadamente \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>125.865 \\ m\u003C/math-field>\u003C/math-field>.",667,133,"an-observer-is-150-meters-away-distance-of-a-hot-air-balloon-online-straight-line-at-ground-level-from-your-position-measures-an-elevation-angle-of-40-up-to-the-base-of-the-balloon-at-what-hei",{"id":86,"category":36,"text_question":87,"photo_question":38,"text_answer":88,"step_text_answer":8,"step_photo_answer":8,"views":89,"likes":90,"slug":91},538080,"A plane ticket has gone up 18%, now costing 4,720.Howmuchdiditcostbeforetheincrease?","\u003Cmathβˆ’fieldreadβˆ’onlydefaultβˆ’mode=\"inlineβˆ’math\"class=\"mathβˆ’expression\">\u003Cmathβˆ’fieldreadβˆ’only>textSolution:\u003C/mathβˆ’field>\u003C/mathβˆ’field>\u003Cbr/>\n1.Definevariables:\u003Cbr/>\nβˆ’Let\u003Cmathβˆ’fieldreadβˆ’onlydefaultβˆ’mode=\"inlineβˆ’math\"class=\"mathβˆ’expression\">\u003Cmathβˆ’fieldreadβˆ’only>P\u003C/mathβˆ’field>\u003C/mathβˆ’field>betheoriginalpriceoftheplaneticket.\u003Cbr/>\nβˆ’\u003Cmathβˆ’fieldreadβˆ’onlydefaultβˆ’mode=\"inlineβˆ’math\"class=\"mathβˆ’expression\">\u003Cmathβˆ’fieldreadβˆ’only>P\u003C/mathβˆ’field>\u003C/mathβˆ’field>increasedby18\\frac{x}{15}=\\frac{4}{3}\u003C/mathβˆ’field>\n\u003Cbr>\n\u003C/div>\n\n\u003Cdiv>\n\n\u003Cmathβˆ’fieldstyle=\"fontβˆ’size:16px;padding:8px;borderβˆ’radius:8px;border:1pxsolidrgba(0,0,0,.3);boxβˆ’shadow:000rgba(0,0,0,.2)\n\"readβˆ’only>x=20\u003C/math-field>\n    \u003Cbr>\n  \u003C/div>",467,93,"15-75-of",{"id":149,"category":36,"text_question":150,"photo_question":38,"text_answer":151,"step_text_answer":8,"step_photo_answer":8,"views":152,"likes":90,"slug":153},538067,"Naria Wants to build a perimeter wall fence around 400 sqm lot. The frontage of the lot is 20 meters. The wall height is 1.2 meters below the ground and 3.8 meters above the ground .\nThe cost of constructing the wall is 750 per square meter. Additionally,she plans to install a 5-meter-wide gate that costs β‚±50,000.\nHow much Maria spend in total for the wall and the gate\na. Php 281,250.00\nb. Php 106,250.00\nc. Php 331,250.00\nd. Php 218,250.00","1. Determine the dimensions of the lot. Given the frontage is 20 meters, calculate the other side using the area:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Area} = 20 \\times x = 400 \u003C/math-field>\u003C/math-field>\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> x = \\frac{400}{20} = 20 \\, \\text{meters} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Calculate the perimeter of the lot:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Perimeter} = 2 \\times (20 + 20) = 80 \\, \\text{meters} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Calculate the total height of the wall:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Total height} = 1.2 + 3.8 = 5 \\, \\text{meters} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. Calculate the wall area excluding the gate:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Wall area} = (\\text{Perimeter} - \\text{Gate width}) \\times \\text{Total height} \u003C/math-field>\u003C/math-field>\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Wall area} = (80 - 5) \\times 5 = 75 \\times 5 = 375 \\, \\text{sqm} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n5. Calculate the cost of the wall:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Wall cost} = 375 \\times 750 = 281,250 \\, \\text{PHP} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n6. Calculate total cost including the gate:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Total cost} = \\text{Wall cost} + \\text{Gate cost} \u003C/math-field>\u003C/math-field>\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Total cost} = 281,250 + 50,000 = 331,250 \\, \\text{PHP} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n7. Therefore, the total cost is: \u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Php} \\, 331,250.00 \u003C/math-field>\u003C/math-field>",727,"naria-wants-to-build-a-perimeter-wall-fence-around-400-sqm-lot-the-frontage-of-the-lot-is-20-meters-the-wall-height-is-1-2-meters-below-the-ground-and-3-8-meters-above-the-ground-the-cost-of-const",{"id":155,"category":36,"text_question":156,"photo_question":38,"text_answer":157,"step_text_answer":8,"step_photo_answer":8,"views":158,"likes":76,"slug":159},538066,"2. A rectangular lot has a\n30 meters.\nallocated along the frontage. What is the gross area\nfrontage of 18 meters and a depth of\nHowever, a public right of way of 3 meters is\nReve\nof\nthe\nlot?\na. 520 sqm\nb. 540 sqm\nC. 560 sqm\nd. 580 sqm\nReV","1. Calculate the area of the rectangular lot without the right of way:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Area}_{\\text{total}} = \\text{frontage} \\times \\text{depth} = 18 \\, \\text{m} \\times 30 \\, \\text{m} = 540 \\, \\text{sqm} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. No need to subtract any area because the problem states that the right of way has already been accounted for in the dimensions provided.\u003Cbr />\n\u003Cbr />\n3. Therefore, the gross area of the lot remains:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> 540 \\, \\text{sqm} \u003C/math-field>\u003C/math-field> \u003Cbr />\n   \u003Cbr />\nThus, the answer is \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>540 \\, \\text{sqm}\u003C/math-field>\u003C/math-field>.",420,"2-a-rectangular-lot-has-a-30-meters-allocated-along-the-frontage-what-is-the-gross-area-frontage-of-18-meters-and-a-depth-of-however-a-public-right-of-way-of-3-meters-is-reve-of-the-lot-a-520-sq",{"id":161,"category":36,"text_question":162,"photo_question":38,"text_answer":163,"step_text_answer":8,"step_photo_answer":8,"views":164,"likes":165,"slug":166},538065,"A triangular lot has a base of 15 meters and heights of 10 meters . What is the total area of the lot ?","1. The formula for the area of a triangle is given by:\u003Cbr />\n\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> A = \\frac{1}{2} \\times \\text{base} \\times \\text{height} \u003C/math-field>\u003C/math-field> \u003Cbr />\n\u003Cbr />\n2. Substitute the given values into the formula:\u003Cbr />\n\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> A = \\frac{1}{2} \\times 15 \\times 10 \u003C/math-field>\u003C/math-field> \u003Cbr />\n\u003Cbr />\n3. Calculate the area:\u003Cbr />\n\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> A = \\frac{1}{2} \\times 150 \u003C/math-field>\u003C/math-field> \u003Cbr />\n\u003Cbr />\n4. Simplify the expression:\u003Cbr />\n\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> A = 75 \u003C/math-field>\u003C/math-field> \u003Cbr />\n\u003Cbr />\nTherefore, the total area of the lot is \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>75 \\, \\text{square meters}\u003C/math-field>\u003C/math-field>.",425,85,"a-triangular-lot-has-a-base-of-15-meters-and-heights-of-10-meters-what-is-the-total-area-of-the-lot",{"id":168,"category":36,"text_question":169,"photo_question":38,"text_answer":170,"step_text_answer":8,"step_photo_answer":8,"views":171,"likes":172,"slug":173},538064,"4x+(x-3)=2x-(3x-4)+5","Solution:\u003Cbr />\n1. Simplify both sides of the equation.\u003Cbr />\n- Left side: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>4x + (x - 3) = 4x + x - 3 = 5x - 3\u003C/math-field>\u003C/math-field>\u003Cbr />\n- Right side: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>2x - (3x - 4) + 5 = 2x - 3x + 4 + 5 = -x + 9\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. The equation is now: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>5x - 3 = -x + 9\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Add \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field> to both sides to eliminate the \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>-x\u003C/math-field>\u003C/math-field> from the right side and simplify:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>5x + x - 3 = 9\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. Simplify: \u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>6x - 3 = 9\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n5. Add 3 to both sides to isolate terms with \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field>:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>6x = 9 + 3\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n6. Simplify:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>6x = 12\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n7. Divide both sides by 6 to solve for \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field>:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x = \\frac{12}{6}\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n8. Simplify the fraction:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x = 2\u003C/math-field>\u003C/math-field>",1332,266,"4x-x-3-2x-3x-4-5",{"first":6,"last":175,"prev":8,"next":10},187,{"current_page":6,"from":6,"last_page":175,"links":177,"path":211,"per_page":212,"to":212,"total":213},[178,181,184,186,188,190,192,195,198,201,204,207,209],{"url":6,"label":179,"active":180},"1",true,{"url":10,"label":182,"active":183},"2",false,{"url":13,"label":185,"active":183},"3",{"url":16,"label":187,"active":183},"4",{"url":19,"label":189,"active":183},"5",{"url":22,"label":191,"active":183},"6",{"url":193,"label":194,"active":183},7,"7",{"url":196,"label":197,"active":183},8,"8",{"url":199,"label":200,"active":183},9,"9",{"url":202,"label":203,"active":183},10,"10",{"url":205,"label":206,"active":183},186,"186",{"url":175,"label":208,"active":183},"187",{"url":10,"label":210,"active":183},"Next »","https://api.math-master.org/api/question",20,3737,{"data":215},{"questions":216},[217,221,225,229,233,237,241,245,249,253,257,261,265,269,273,277,281,285,289,293],{"id":218,"category":36,"text_question":219,"slug":220},532033,"𝑦 = ( π‘₯2 βˆ’ 3) (π‘₯3 + 2 π‘₯ + 1)","y-x2-3-x3-2-x-1",{"id":222,"category":36,"text_question":223,"slug":224},532093,"Karina has a plot of 5000 square meters in which she has decided that 60% of it will be used to plant vegetables. Of this part, 12% will be dedicated to planting lettuce. How much surface area of the plot will be used to grow lettuce?","karina-has-a-plot-of-5000-square-meters-in-which-she-has-decided-that-60-of-it-will-be-used-to-plant-vegetables-of-this-part-12-will-be-dedicated-to-planting-lettuce-how-much-surface-area-of-the",{"id":226,"category":36,"text_question":227,"slug":228},533985,"Serum cholesterol levels in men aged 18 to 24 years have a normal distribution with a mean\n 178.1mg/100 ml and standard deviation 40.7 mg/100 ml.\n The. Randomly choosing a man between 18 and 24 years old, determine the probability of\n your serum cholesterol level is less than 200.\n B. Whether a serum cholesterol level should be judged too high if it is above 7%\n higher, determine the value of the separation level of levels that are too high.\n w. Determine a 90% reference range for serum cholesterol level among men\n from 18 to 24 years old.","serum-cholesterol-levels-in-men-aged-18-to-24-years-have-a-normal-distribution-with-a-mean-178-1mg-100-ml-and-standard-deviation-40-7-mg-100-ml-the-randomly-choosing-a-man-between-18-and-24-years",{"id":230,"category":36,"text_question":231,"slug":232},534071,"There are 162 students enrolled in the basic mathematics course. If the number of women is 8 times the number of men, how many women are there in the basic mathematics course?","there-are-162-students-enrolled-in-the-basic-mathematics-course-if-the-number-of-women-is-8-times-the-number-of-men-how-many-women-are-there-in-the-basic-mathematics-course",{"id":234,"category":36,"text_question":235,"slug":236},534100,"Reparameterize the curve r(t)= cos(t)i without (t)j (t)k by the arc length.","reparameterize-the-curve-r-t-cos-t-i-without-t-j-t-k-by-the-arc-length",{"id":238,"category":36,"text_question":239,"slug":240},534110,"-3(-4x+5)=-6(7x-8)+9-10x","3-4x-5-6-7x-8-9-10x",{"id":242,"category":36,"text_question":243,"slug":244},534112,"What is the total tolerance for a dimension from 1.996\" to 2.026*?","what-is-the-total-tolerance-for-a-dimension-from-1-996-to-2-026",{"id":246,"category":36,"text_question":247,"slug":248},534213,"Suppose that you use 4.29 g of Iron in the chemical reaction: 2Fe(s) + 3\nCu2 + (aq) 2Fe 3 + (aq) + 3Cu(s\n) - . What is the theoretical yield of Cu (s), in grams?","suppose-that-you-use-4-29-g-of-iron-in-the-chemical-reaction-2fe-s-3-cu2-aq-2fe-3-aq-3cu-s-what-is-the-theoretical-yield-of-cu-s-in-grams",{"id":250,"category":36,"text_question":251,"slug":252},534245,"19) If the temperature of -8Β°C decreases by 12Β°C, how much will it be?\n\n a)-20Β°C\n\n -4Β°C\n\n c) 4Β°C\n\n d) 20Β°C","19-if-the-temperature-of-8-c-decreases-by-12-c-how-much-will-it-be-a-20-c-4-c-c-4-c-d-20-c",{"id":254,"category":36,"text_question":255,"slug":256},534298,"30y - y . y = 144","30y-y-y-144",{"id":258,"category":36,"text_question":259,"slug":260},534310,"(2m+3)(4m+3)=0","2m-3-4m-3-0",{"id":262,"category":36,"text_question":263,"slug":264},534316,"XΒ³-27","x-27",{"id":266,"category":36,"text_question":267,"slug":268},534383,"Find the number of pounds of nails required for 17850 square feet of drywall if each thousand square feet requires 4.5 pounds of nails.","find-the-number-of-pounds-of-nails-required-for-17850-square-feet-of-drywall-if-each-thousand-square-feet-requires-4-5-pounds-of-nails",{"id":270,"category":36,"text_question":271,"slug":272},534392,"a survey showed that 3 out of 7 voters would vote in an election. based on this survey, how many people would vote in a city with 25,000 people?","a-survey-showed-that-3-out-of-7-voters-would-vote-in-an-election-based-on-this-survey-how-many-people-would-vote-in-a-city-with-25-000-people",{"id":274,"category":36,"text_question":275,"slug":276},534410,"36 cars of the same model that were sold in a\n dealership, and the number of days that each one remained in the dealership yard before being sold is determined. The sample average is 9.75 days, with a sample standard deviation of\n 2, 39 days. Construct a 95% confidence interval for the population mean number of days\n that a car remains on the dealership's forecourt","36-cars-of-the-same-model-that-were-sold-in-a-dealership-and-the-number-of-days-that-each-one-remained-in-the-dealership-yard-before-being-sold-is-determined-the-sample-average-is-9-75-days-with-a",{"id":278,"category":36,"text_question":279,"slug":280},534513,"Given a circle π‘˜(𝑆; π‘Ÿ = 4 π‘π‘š) and a line |𝐴𝐡| = 2 π‘π‘š. Determine and construct the set of all\ncenters of circles that touch circle π‘˜ and have radius π‘Ÿ = |𝐴𝐡|","given-a-circle-k-s-r-4-cm-and-a-line-ab-2-cm-determine-and-construct-the-set-of-all-centers-of-circles-that-touch-circle-k-and-have-radius-r-ab",{"id":282,"category":36,"text_question":283,"slug":284},534518,"Farm Grown, Inc., produces cases of perishable food products. Each case contains an assortment of vegetables and other farm products. Each case costs5 and sells for 15.Ifthereareanynotsoldbytheendoftheday,theyaresoldtoalargefoodprocessingcompanyfor3 a case. The probability that daily demand will be 100 cases is 0.30, the probability that daily demand will be 200 cases is 0.40, and the probability that daily demand will be 300 cases is 0.30. Farm Grown has a policy of always satisfying customer demands. If its own supply of cases is less than the demand, it buys the necessary vegetables from a competitor. The estimated cost of doing this is 16percase.(a)Drawadecisiontableforthisproblem(b)Whatdoyourecommend?","farmβˆ’grownβˆ’incβˆ’producesβˆ’casesβˆ’ofβˆ’perishableβˆ’foodβˆ’productsβˆ’eachβˆ’caseβˆ’containsβˆ’anβˆ’assortmentβˆ’ofβˆ’vegetablesβˆ’andβˆ’otherβˆ’farmβˆ’productsβˆ’eachβˆ’caseβˆ’costsβˆ’5βˆ’andβˆ’sellsβˆ’forβˆ’15βˆ’ifβˆ’thereβˆ’areβˆ’anyβˆ’notβˆ’soldβˆ’by","id":286,"category":36,"textquestion":287,"slug":288,534543,"1.Thecosttotransport250packagesofcement120kilometersis600. What will be the cost to transport 500 packages 300 kilometers?","1-the-cost-to-transport-250-packages-of-cement-120-kilometers-is-600-what-will-be-the-cost-to-transport-500-packages-300-kilometers",{"id":290,"category":36,"text_question":291,"slug":292},534659,"Slope 7,3 and 9,5","slope-7-3-and-9-5",{"id":294,"category":36,"text_question":295,"slug":296},534691,"5 1/9 + 2 2/3","5-1-9-2-2-3",{"data":298},{"id":299,"category":36,"slug":300,"text_question":301,"photo_question":8,"text_answer":302,"step_text_answer":8,"step_photo_answer":8,"views":303,"likes":41,"expert":304},534302,"the-function-h-t-5t-2-20t-60-models-the-height-in-meters-of-a-ball-t-seconds-after-it-s-thrown-which-describe-the-intercepts-and-vertex-of-this-function","The function ht=-5t^2+20t+60 models the height in meters of a ball t seconds after it’s thrown .\nWhich describe the intercepts and vertex of this function","To find the intercepts of the function ht = -5t^2 + 20t + 60, we need to set it equal to zero and solve for t.\u003Cbr />\u003Cbr />1. Set ht = 0:\u003Cbr />-5t^2 + 20t + 60 = 0\u003Cbr />\u003Cbr />2. Solve the quadratic equation using the quadratic formula:\u003Cbr />t = \\frac{-b \\pm \\sqrt{b^2 - 4ac}}{2a}\u003Cbr />\u003Cbr />In this case, a = -5, b = 20, and c = 60. Plugging these values into the quadratic formula:\u003Cbr />\u003Cbr />t = \\frac{-20 \\pm \\sqrt{20^2 - 4βˆ’560}}{2βˆ’5}\u003Cbr />\u003Cbr />3. Simplify the equation:\u003Cbr />t = \\frac{-20 \\pm \\sqrt{400 + 1200}}{-10}\u003Cbr />t = \\frac{-20 \\pm \\sqrt{1600}}{-10}\u003Cbr />t = \\frac{-20 \\pm 40}{-10}\u003Cbr />\u003Cbr />4. Solve for t:\u003Cbr />Case 1: \u003Cbr />t = \\frac{-20 + 40}{-10}\u003Cbr />t = -2\u003Cbr />\u003Cbr />Case 2:\u003Cbr />t = \\frac{-20 - 40}{-10}\u003Cbr />t = 6\u003Cbr />\u003Cbr />Therefore, the intercepts of the function ht are t = -2 and t = 6. This means that the graph of the function crosses the t-axis at t = -2 and t = 6.\u003Cbr />\u003Cbr />To find the vertex of the function, we can use the formula for the x-coordinate of the vertex, which is given by:\u003Cbr />\u003Cbr />x = -\\frac{b}{2a}\u003Cbr />\u003Cbr />In this case, a = -5 and b = 20. Plugging these values into the formula:\u003Cbr />\u003Cbr />x = -\\frac{20}{2βˆ’5}\u003Cbr />x = -\\frac{20}{-10}\u003Cbr />x = 2\u003Cbr />\u003Cbr />To find the y-coordinate of the vertex, we substitute the x-coordinate back into the function:\u003Cbr />\u003Cbr />h2 = -52^2 + 202 + 60\u003Cbr />h2 = -20 + 40 + 60\u003Cbr />h2 = 80\u003Cbr />\u003Cbr />Therefore, the vertex of the function ht is 2,80.\u003Cbr />\u003Cbr />Answer:\u003Cbr />The intercepts of the function ht = -5t^2 + 20t + 60 are t = -2 and t = 6.\u003Cbr />The vertex of the function ht is 2,80.",1253,{"id":305,"name":306,"photo":307,"biography":308,"created_at":8,"updated_at":8,"rating":309,"total_answer":310},25,"Santino","https://api.math-master.org/img/experts/25/25.webp","When I was in school I was the best student in my class.\r\nI was the topper of my class in mathematics subject. I won 4 district-level and 2 provincial-level mathematics quizzes in my School life.\r\nMy Teacher felt proud of my performance.\r\nAfter that, I chose Pre Engineering in college.\r\nIn Pre Engineering I got 90% Marks in Mathematics. In 2018 I started a Bachelor of Engineering in which Mathematical Use was Maximum.",4.5,110,{"data":312},{"questions":313},[314,318,322,326,330,334,338,342,346,350,354,358,362,366,370,374,378,382,386,390],{"id":315,"category":36,"text_question":316,"slug":317},532011,"Convert the following function from standard form to vertex form \nfx = x^2 + 7x - 1","convert-the-following-function-from-standard-form-to-vertex-form-f-x-x-2-7x-1",{"id":319,"category":36,"text_question":320,"slug":321},532054,"A software company incurs a cost of 50perlicensesoldplus5,000 in fixed costs. How many licenses should you sell to minimize total costs?","a-software-company-incurs-a-cost-of-50-per-license-sold-plus-5-000-in-fixed-costs-how-many-licenses-should-you-sell-to-minimize-total-costs",{"id":323,"category":36,"text_question":324,"slug":325},532055,"A college believes that 22% of applicants to that school have parents who have remarried. How large a sample is needed to estimate the true proportion of students who have parents who have remarried to within 5 percentage points?","a-college-believes-that-22-of-applicants-to-that-school-have-parents-who-have-remarried-how-large-a-sample-is-needed-to-estimate-the-true-proportion-of-students-who-have-parents-who-have-remarried-t",{"id":327,"category":36,"text_question":328,"slug":329},533895,"what is 456456446+24566457","what-is-456456446-24566457",{"id":331,"category":36,"text_question":332,"slug":333},533937,"The ratio of tomatoes to red apples is 2:5. If there are 20 tomaoes in the garden, how many red apples are there?","the-ratio-of-tomatoes-to-red-apples-is-2-5-if-there-are-20-tomaoes-in-the-garden-how-many-red-apples-are-there",{"id":335,"category":36,"text_question":336,"slug":337},533977,"what is the annual rate on ​525 at 0.046​% per day for 3 months?","what-is-the-annual-rate-on-525-at-0-046-per-day-for-3-months",{"id":339,"category":36,"text_question":340,"slug":341},534029,"A job takes 9\n workers 92\n hours to finish. How many hours would it take 5\n workers to complete the same job?","a-job-takes-9-workers-92-hours-to-finish-how-many-hours-would-it-take-5-workers-to-complete-the-same-job",{"id":343,"category":36,"text_question":344,"slug":345},534032,"The miles per gallon (mpg) for each of 20 medium-sized cars selected from a production line during the month of March are listed below.\r\n23.0\t21.2\t23.5\t23.6\r\n20.1\t24.3\t25.2\t26.9\r\n24.6\t22.6\t26.1\t23.1\r\n25.8\t24.6\t24.3\t24.1\r\n24.8\t22.1\t22.8\t24.5\r\n(a)\r\nFind the z-scores for the largest measurement. (Round your answers to two decimal places.)\r\nz =","the-miles-per-gallon-mpg-for-each-of-20-medium-sized-cars-selected-from-a-production-line-during-the-month-of-march-are-listed-below-23-0-21-2-23-5-23-6-20-1-24-3-25-2-26-9-24-6-22-6-26-1-23-1",{"id":347,"category":36,"text_question":348,"slug":349},534084,"Determine the minimum degree that an algebraic equation can assume knowing that it admits 2 as a double root and -i as a triple root","determine-the-minimum-degree-that-an-algebraic-equation-can-assume-knowing-that-it-admits-2-as-a-double-root-and-i-as-a-triple-root",{"id":351,"category":36,"text_question":352,"slug":353},534108,"prove that if n odd integer then n^2+5 is even","prove-that-if-n-odd-integer-then-n-2-5-is-even",{"id":355,"category":36,"text_question":356,"slug":357},534214,"Nice's central library building is considered one of the most original in the world, as it is a mix between a sculpture and a work of habitable architecture. It was called La TΓͺte CarrΓ©e and is made up of part of a bust that supports a cube divided into five floors.\n It is known that the building has a total height of approximately 30 meters. It admits that the cubic part of the sculpture is parallel to the floor and has a volume of 2744 meters3\n Calculate, in meters, the height of the bust that supports the cube.\n Displays all the calculations you made.","nice-s-central-library-building-is-considered-one-of-the-most-original-in-the-world-as-it-is-a-mix-between-a-sculpture-and-a-work-of-habitable-architecture-it-was-called-la-tete-carree-and-is-made-u",{"id":359,"category":36,"text_question":360,"slug":361},534265,"If a two-branch parallel current divider network, if the resistance of one branch is doubled while keeping all other factors constant, what happens to the current flow through that branch and the other branch?\n\nSelect one:\n\na. The current through the doubled resistance branch remains unchanged, and the current through the other branch decreases.\n\nb. The current through the doubled resistance branch decreases, and the current through the other branch remains unchanged.\n\nc. The current through the doubled resistance branch increases, and the current through the other branch remains unchanged.\n\nd. The current through both branches remain unchanged.","if-a-two-branch-parallel-current-divider-network-if-the-resistance-of-one-branch-is-doubled-while-keeping-all-other-factors-constant-what-happens-to-the-current-flow-through-that-branch-and-the-othe",{"id":363,"category":36,"text_question":364,"slug":365},534406,"During a month's time, an automobile sales person receives a 6% commission on the first 5000 in sales, a 7% commission on the next 5000 sales, 8% commission on anything over 10,000. What is her commission for 36,000 in sales?","during-a-month-s-time-an-automobile-sales-person-receives-a-6-commission-on-the-first-5000-in-sales-a-7-commission-on-the-next-5000-sales-8-commission-on-anything-over-10-000-what-is-her-com",{"id":367,"category":36,"text_question":368,"slug":369},534408,"Which statement best describes the key changes in perspectives on inclusion?\r\n\r\n\t\t\r\nAn inclusive program must consider the unique experiences of every child and family as well as the child's strengths and needs.\r\n\r\n\t\t\r\nThere is a shift in thinking about individual programs as \"inclusive programs\" to thinking about inclusion as something that reflects the cultural influence of the family.\r\n\r\n\t\t\r\nThere is a greater emphasis on barriers to full participation and the acknowledgement that all children are unique and must be fully and meaningfully engaged in a program.\r\n\r\n\t\t\r\nIn an inclusive program all participants are accepted by their peers and other members of the community.","which-statement-best-describes-the-key-changes-in-perspectives-on-inclusion-an-inclusive-program-must-consider-the-unique-experiences-of-every-child-and-family-as-well-as-the-child-s-strengths",{"id":371,"category":36,"text_question":372,"slug":373},534455,"Total Users with an active Wise account = Total Active Users + Total Users who haven’t transacted\r\nTotal Active Users = Total MCA Users + Total Send Users = Total New Users + Retained Users\r\nTotal New Users = New Send Users + New MCA Users\r\nTotal MCA Users = New MCA Users + Retained Users who transacted this month via MCA\r\nTotal Send Users = New Send Users + Retained Users who transacted this month via Send\r\n\r\nSend CR = Total Send Users / Total Users with an active Wise account\r\nMCA CR = Total MCA Users / Total Users with an active Wise account\r\n\r\nNew Send CR = New Send Users / New Profiles Created in Month\r\nNew MCA CR = New MCA Users / New Profiles Created in Month\r\n\r\nWe have recently witnessed a drop in MCA conversion, but send user conversion is\r\nstable, can you help explain why?","total-users-with-an-active-wise-account-total-active-users-total-users-who-haven-t-transacted-total-active-users-total-mca-users-total-send-users-total-new-users-retained-users-total-new",{"id":375,"category":36,"text_question":376,"slug":377},534464,"solid obtained by rotation around the axis x = -1, the region delimited by x^2 - x + y = 0 and the abscissa axis","solid-obtained-by-rotation-around-the-axis-x-1-the-region-delimited-by-x-2-x-y-0-and-the-abscissa-axis",{"id":379,"category":36,"text_question":380,"slug":381},534552,"Solve for z:\n\n2z-6=10z+2","solve-for-z-2z-6-10z-2",{"id":383,"category":36,"text_question":384,"slug":385},534622,"It costs a manufacturer 2,500 to purchase the tools to manufacture a certain homemade item. If the cost for materials and labor is 60Β’ per item produced, and if the manufacturer can sell each item for 90Β’, find how many items must he produce and sell to make a profit of 2000?","it-costs-a-manufacturer-2-500-to-purchase-the-tools-to-manufacture-a-certain-homemade-item-if-the-cost-for-materials-and-labor-is-60-per-item-produced-and-if-the-manufacturer-can-sell-each-item-fo",{"id":387,"category":36,"text_question":388,"slug":389},534645,"Find the distance from the point (2,-1) to the line 2x-5y+10=0","find-the-distance-from-the-point-2-1-to-the-line-2x-5y-10-0",{"id":391,"category":36,"text_question":392,"slug":393},534672,"I have a complex function I would like to integrate over. I can use two approaches and they should give the same solution. If I want to find the contour integral βˆ«π›Ύπ‘§Β―π‘‘π‘§\r\n for where 𝛾\r\n is the circle |π‘§βˆ’π‘–|=3\r\n oriented counterclockwise I get the following:\r\n\r\n∫2πœ‹0𝑖+3π‘’π‘–π‘‘βŽ―βŽ―βŽ―βŽ―βŽ―βŽ―βŽ―βŽ―βŽ―βŽ―βŽ―βŽ―βŽ―βŽ―βŽ―βŽ―βŽ―π‘‘(𝑖+3𝑒𝑖𝑑)=∫2πœ‹03𝑖(βˆ’π‘–+3π‘’βˆ’π‘–π‘‘)𝑒𝑖𝑑𝑑𝑑=18πœ‹π‘–\r\n\r\nIf I directly apply the Residue Theorem, I would get\r\n\r\nβˆ«π›Ύπ‘§Β―π‘‘π‘§=2πœ‹π‘–Res(𝑓,𝑧=0)=2πœ‹π‘–","i-have-a-complex-function-i-would-like-to-integrate-over-i-can-use-two-approaches-and-they-should-give-the-same-solution-if-i-want-to-find-the-contour-integral-z-dz-for-where-is-the-circle",{"data":395},[396,400,404],{"id":397,"question":398,"answer":399},108104,"Math question: \"Graph the line with a slope of 2 and a y-intercept of -3. What is the x-coordinate when the y-coordinate is 5?\"","Answer: To graph the line, plot the point (-3, 0) as the y-intercept, then find the point (x, y) where y = 5. Using the slope formula (m = Ξ”y/Ξ”x), we have (5-0)/(x-(-3)) = 2. Solving for x gives 22/2 = x - (-3), so x = 19. Hence, the x-coordinate when y = 5 is 19.",{"id":401,"question":402,"answer":403},113930,"What is the resultant of multiplying vector A(3, -2) by vector B(4, 5)?","The resultant of multiplying vector A by vector B is vector C(12, -10).",{"id":405,"question":406,"answer":407},102917,"Question: What is 2/5 expressed as a percent?","Answer: To convert a fraction to a percent, we multiply it by 100. So, multiplying 2/5 by 100 gives us 40%. Therefore, 2/5 as a percent is 40%.",{"sicons":409},{"bxl:facebook-circle":410,"bxl:instagram":414,"mdi:web":416,"la:apple":418,"ph:google-logo-bold":421,"ph:google-logo":424},{"left":411,"top":411,"width":412,"height":412,"rotate":411,"vFlip":183,"hFlip":183,"body":413},0,24,"\u003Cpath fill=\"currentColor\" d=\"M12.001 2.002c-5.522 0-9.999 4.477-9.999 9.999c0 4.99 3.656 9.126 8.437 9.879v-6.988h-2.54v-2.891h2.54V9.798c0-2.508 1.493-3.891 3.776-3.891c1.094 0 2.24.195 2.24.195v2.459h-1.264c-1.24 0-1.628.772-1.628 1.563v1.875h2.771l-.443 2.891h-2.328v6.988C18.344 21.129 22 16.992 22 12.001c0-5.522-4.477-9.999-9.999-9.999\"/>",{"left":411,"top":411,"width":412,"height":412,"rotate":411,"vFlip":183,"hFlip":183,"body":415},"\u003Cpath fill=\"currentColor\" d=\"M11.999 7.377a4.623 4.623 0 1 0 0 9.248a4.623 4.623 0 0 0 0-9.248m0 7.627a3.004 3.004 0 1 1 0-6.008a3.004 3.004 0 0 1 0 6.008\"/>\u003Ccircle cx=\"16.806\" cy=\"7.207\" r=\"1.078\" fill=\"currentColor\"/>\u003Cpath 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