A nondegenerate ideal gas of diatomic molecules with a kilomolar mass of 2 kg/kmol and a characteristic rotational temperature of 86 K is adsorbed on the walls of a container, where the binding energy is 0.02 eV. The adsorbed molecules move freely on the walls, and their rotation is confined to the plane of the walls. Calculate the surface density of adsorbed molecules at 12 K if the gas pressure is 103 Pa! What result would you get at 68 K and the same pressure?

Name: Solved: A nondegenerate ideal gas of diatomic molecules with a kilomolar mass of 2 kg/kmol and a characteristic rotational temperature of 86 K is adsorbed on the walls of a container, where the binding energy is 0.02 eV. The adsorbed molecules move freely on the walls, and their rotation is confined to the plane of the walls. Calculate the surface density of adsorbed molecules at 12 K if the gas pressure is 103 Pa! What result would you get at 68 K and the same pressure? - MathMaster
Brand: MathMaster
Rating: 4.9 (98 reviews)

likes

488 views

Answer to a math question A nondegenerate ideal gas of diatomic molecules with a kilomolar mass of 2 kg/kmol and a characteristic rotational temperature of 86 K is adsorbed on the walls of a container, where the binding energy is 0.02 eV. The adsorbed molecules move freely on the walls, and their rotation is confined to the plane of the walls. Calculate the surface density of adsorbed molecules at 12 K if the gas pressure is 103 Pa! What result would you get at 68 K and the same pressure?

$Expert avatar$

Madelyn

4.7

86 Answers

To calculate the surface density of adsorbed molecules, we can use the Langmuir adsorption isotherm equation: Γ = (P * A) / (k * T) where: Γ is the surface density of adsorbed molecules in mol/m², P is the gas pressure in Pa, A is the binding energy per molecule in J, k is the Boltzmann constant (1.38 x 10^-23 J/K), T is the temperature in Kelvin. First, let's convert the binding energy from eV to J: 1 eV = 1.602 x 10^-19 J So, the binding energy is 0.02 eV * 1.602 x 10^-19 J/eV = 3.204 x 10^-21 J. Now, let's calculate the surface density at 12 K: Γ₁ = (103 Pa * 3.204 x 10^-21 J) / (1.38 x 10^-23 J/K * 12 K) Γ₁ ≈ 1.87 x 10^5 mol/m² Next, let's calculate the surface density at 68 K: Γ₂ = (103 Pa * 3.204 x 10^-21 J) / (1.38 x 10^-23 J/K * 68 K) Γ₂ ≈ 5.26 x 10^4 mol/m² Therefore, at 12 K and a gas pressure of 103 Pa, the surface density of adsorbed molecules is approximately 1.87 x 10^5 mol/m², while at 68 K and the same pressure, the surface density is approximately 5.26 x 10^4 mol/m².

Frequently asked questions (FAQs)

Math Question: Find the median of a data set {3, 5, 8, 12, 15, 17, 19} using the Median Theorem.

Math question: In a circle, if angle AOB is 90 degrees, find the measure of angle ACB.

Question: Find the product of two consecutive numbers, where the sum of the numbers is 15.

New questions in Mathematics

How to find the value of x and y which satisfy both equations x-2y=24 and 8x-y=117

Let 𝑢 = 𝑓(𝑥, 𝑦) = (𝑒^𝑥)𝑠𝑒𝑛(3𝑦). Check if 9((𝜕^2) u / 𝜕(𝑥^2)) +((𝜕^2) 𝑢 / 𝜕(𝑦^2)) = 0

The ratio of tomatoes to red apples is 2:5. If there are 20 tomaoes in the garden, how many red apples are there?

Credit title that represents a payment order. This model, which emerged in Brazil, can only be issued in two specific situations: in the purchase and sale of commercial products or in the provision of services. Select the correct alternative: Question 6Answer The. Present value B. Promissory note w. Present value d. Duplicate It is. Bill of exchange

2x2 and how much?

Pedro had 80% of the amount needed to buy a game. Of this amount, you spent 15% on a watch and therefore, you will need to add another R$640.00 to purchase this game. Is the value of the game?

find all matrices that commute with the matrix A=[0 1]