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# Solve the equation: sin$2x$ = 0.35 Where 0° ≤ x ≤ 360°. Give your answers to 1 d.p.

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## Answer to a math question Solve the equation: sin$2x$ = 0.35 Where 0° ≤ x ≤ 360°. Give your answers to 1 d.p.

Fred
4.4
$\sin\left${2x}\right$=\frac{ 7 }{ 20 }$
$2x=\arcsin\left${\frac{ 7 }{ 20 }}\right$$
$\begin{array} { l }2x=\arcsin\left${\frac{ 7 }{ 20 }}\right$,\\2x={180}\degree-\arcsin\left${\frac{ 7 }{ 20 }}\right$\end{array}$
$\begin{array} { l }\begin{array} { l }2x=\arcsin\left${\frac{ 7 }{ 20 }}\right$+{360}\degreek,& k \in ℤ\end{array},\\2x={180}\degree-\arcsin\left${\frac{ 7 }{ 20 }}\right$\end{array}$
$\begin{array} { l }\begin{array} { l }2x=\arcsin\left${\frac{ 7 }{ 20 }}\right$+{360}\degreek,& k \in ℤ\end{array},\\\begin{array} { l }2x={180}\degree-\arcsin\left${\frac{ 7 }{ 20 }}\right$+{360}\degreek,& k \in ℤ\end{array}\end{array}$
$\begin{array} { l }\begin{array} { l }x=\frac{ \arcsin\left${\frac{ 7 }{ 20 }}\right$ }{ 2 }+{180}\degreek,& k \in ℤ\end{array},\\\begin{array} { l }2x={180}\degree-\arcsin\left${\frac{ 7 }{ 20 }}\right$+{360}\degreek,& k \in ℤ\end{array}\end{array}$
$\begin{array} { l }\begin{array} { l }x=\frac{ \arcsin\left${\frac{ 7 }{ 20 }}\right$ }{ 2 }+{180}\degreek,& k \in ℤ\end{array},\\\begin{array} { l }x={90}\degree-\frac{ \arcsin\left${\frac{ 7 }{ 20 }}\right$ }{ 2 }+{180}\degreek,& k \in ℤ\end{array}\end{array}$
$\begin{array} { l }\begin{array} { l }x\approx{10.2}\degree+{180}\degreek,& k \in ℤ\end{array},\\\begin{array} { l }x\approx{79.8}\degree+{180}\degreek,& k \in ℤ\end{array}\end{array}$

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