Solve the equation: sin(2x) = 0.35 Where 0° ≤ x ≤ 360°. Give your answers to 1 d.p.



Answer to a math question Solve the equation: sin(2x) = 0.35 Where 0° ≤ x ≤ 360°. Give your answers to 1 d.p.

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$\sin\left({2x}\right)=\frac{ 7 }{ 20 }$
$2x=\arcsin\left({\frac{ 7 }{ 20 }}\right)$
$\begin{array} { l }2x=\arcsin\left({\frac{ 7 }{ 20 }}\right),\\2x={180}\degree-\arcsin\left({\frac{ 7 }{ 20 }}\right)\end{array}$
$\begin{array} { l }\begin{array} { l }2x=\arcsin\left({\frac{ 7 }{ 20 }}\right)+{360}\degreek,& k \in ℤ\end{array},\\2x={180}\degree-\arcsin\left({\frac{ 7 }{ 20 }}\right)\end{array}$
$\begin{array} { l }\begin{array} { l }2x=\arcsin\left({\frac{ 7 }{ 20 }}\right)+{360}\degreek,& k \in ℤ\end{array},\\\begin{array} { l }2x={180}\degree-\arcsin\left({\frac{ 7 }{ 20 }}\right)+{360}\degreek,& k \in ℤ\end{array}\end{array}$
$\begin{array} { l }\begin{array} { l }x=\frac{ \arcsin\left({\frac{ 7 }{ 20 }}\right) }{ 2 }+{180}\degreek,& k \in ℤ\end{array},\\\begin{array} { l }2x={180}\degree-\arcsin\left({\frac{ 7 }{ 20 }}\right)+{360}\degreek,& k \in ℤ\end{array}\end{array}$
$\begin{array} { l }\begin{array} { l }x=\frac{ \arcsin\left({\frac{ 7 }{ 20 }}\right) }{ 2 }+{180}\degreek,& k \in ℤ\end{array},\\\begin{array} { l }x={90}\degree-\frac{ \arcsin\left({\frac{ 7 }{ 20 }}\right) }{ 2 }+{180}\degreek,& k \in ℤ\end{array}\end{array}$
$\begin{array} { l }\begin{array} { l }x\approx{10.2}\degree+{180}\degreek,& k \in ℤ\end{array},\\\begin{array} { l }x\approx{79.8}\degree+{180}\degreek,& k \in ℤ\end{array}\end{array}$

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