Question

In a cheese factory, one pie costs 3800 denars. The fixed ones costs are 1,200,000 denars, and variable costs are 2,500 denars per pie. To encounter: a) income functions. profit and costs; b) the break-even point and profit and loss intervals.

197

likes
987 views

Answer to a math question In a cheese factory, one pie costs 3800 denars. The fixed ones costs are 1,200,000 denars, and variable costs are 2,500 denars per pie. To encounter: a) income functions. profit and costs; b) the break-even point and profit and loss intervals.

Expert avatar
Eliseo
4.6
110 Answers
a) To find the income function, we can use the formula:
Income = Price per pie * Number of pies sold

In this case, the price per pie is 3800 denars. Let's denote the number of pies sold as 'x'. Therefore, the income function is:
Income = 3800x

To find the profit function, we need to subtract the total cost from the income. The total cost includes both fixed costs and variable costs. The fixed costs are 1,200,000 denars and the variable cost per pie is 2500 denars. So, the total cost function is:
Total Cost = Fixed Costs + Variable Cost per pie * Number of pies sold
Total Cost = 1,200,000 + 2500x

Now, we can find the profit function:
Profit = Income - Total Cost
Profit = 3800x - (1,200,000 + 2500x)
Simplifying this equation, we get:
Profit = 3800x - 1200000 - 2500x
Profit = 1300x - 1200000

b) The break-even point is the point where the profit is zero. To find the break-even point, we set the profit function equal to zero and solve for 'x':
1300x - 1200000 = 0
1300x = 1200000
x = 1200000/1300
x β‰ˆ 923.08

Therefore, the break-even point is approximately 923.08 pies.

To find the profit and loss intervals, we need to analyze the profit function. If the profit is positive, it indicates a profit. If the profit is negative, it indicates a loss. If the profit is zero, it indicates the break-even point.

Let's consider two cases:
1. When x < 923.08 (before the break-even point):
Plugging in numbers less than 923.08 into the profit function, we will get a negative value. This indicates a loss.

2. When x > 923.08 (after the break-even point):
Plugging in numbers greater than 923.08 into the profit function, we will get a positive value. This indicates a profit.

Answer:
a) The income function is Income = 3800x
The profit function is Profit = 1300x - 1200000
The total cost function is Total Cost = 1,200,000 + 2500x

b) The break-even point is approximately 923.08 pies.
Before the break-even point, there is a loss.
After the break-even point, there is a profit.

Frequently asked questions (FAQs)
Math question: How many ways can 3 students be chosen out of 10 students?
+
What is the number of ways to arrange the letters of the word "COMBINATION"?
+
Math question: Find the 5th order derivative of f(x) = 3x^4 - 2x^3 + 5x^2 - 7x + 1.
+
New questions in Mathematics
A particular employee arrives at work sometime between 8:00 a.m. and 8:50 a.m. Based on past experience the company has determined that the employee is equally likely to arrive at any time between 8:00 a.m. and 8:50 a.m. Find the probability that the employee will arrive between 8:05 a.m. and 8:40 a.m. Round your answer to four decimal places, if necessary.
11(4x-9)= -319
8x-(5-x)
x/20*100
(-5/6)-(-5/4)
Estimate the quotient for 3.24 Γ· 82
X~N(2.6,1.44). find the P(X<3.1)
ind the z-score for which 72% of the distribution's area lies between -z and z. -1.7417, 1.7417 -1.1538, 1.1538 -1.0803, 1.0803 -2.826, 2.826
Your grandfather has run a small high street pharmacy for 40 years. After much persuasion, he has agreed to open a digital store online. List 5 potential ways to improve sales and/or margins by having a digital pharmacy through the utilisation of historic or new sales data.
Let f and g be defined in R and suppose that there exists M > 0 such that |f(x) βˆ’ f(p)| ≀ M|g(x) βˆ’ g(p)|, for all x. Prove that if g is continuous in p, then f will also be continuous in p.
48 kg of 30% sulfuric acid in a mixture of 10% and 40% sulfuric acid arose. How many kilograms were each of the original solutions?
nI Exercises 65-68, the latitudes of a pair of cities are given. Assume that one city si directly south of the other and that the earth is a perfect sphere of radius 4000 miles. Use the arc length formula in terms of degrees to find the distance between the two cities. 65. The North Pole: latitude 90Β° north Springfield, Illinois: latitude 40Β° north
Determine the kinetic energy of a baseball whose mass is 100 grams and has a speed of 30 m/s.
Kayla started a book club at her school. The number of girls in the book club was one more than twice the number of boys. If there are 15 girls in the book club, how many boys are in the club?
How many digits are there in Hindu-Arabic form of numeral 26 Γ— 1011
8(x+4) -4=4x-1
3(x-4)=156
2p-6=8+5(p+9)
The length of a rectangle is five more than its width. if the perimeter is 120, find both the length and the width.
Exercise The temperature T in degrees Celsius of a chemical reaction is given as a function of time t, expressed in minutes, by the function defined on ΒΏ by: T (t )=(20 t +10)eβˆ’0.5t. 1) What is the initial temperature? 2) Show that T' (t )=(βˆ’10 t +15)eβˆ’0 .5t. 3) Study the sign of T' (t ), then draw up the table of variations of T . We do not ask for the limit of T in +∞. 4) What is the maximum temperature reached by the reaction chemical. We will give an approximate value to within 10βˆ’2. 5) After how long does the temperature T go back down to its initial value? We will give an approximate value of this time in minutes and seconds. DM 2: study of a function Exercise The temperature T in degrees Celsius of a chemical reaction is given as a function of time t, expressed in minutes, by the function defined on ΒΏ by: T (t )=(20 t +10)eβˆ’0.5t. 1) What is the initial temperature? 2) Show that T' (t )=(βˆ’10 t +15)eβˆ’0.5 t. 3) Study the sign of T' (t ), then draw up the table of variations of T . We do not ask for the limit of T in +∞. 4) What is the maximum temperature reached by the reaction chemical. We will give an approximate value to within 10βˆ’2. 5) After how long does the temperature T go back down to its initial value? We will give an approximate value of this time in minutes and seconds.