Question
The graph of the equation x²= 4py is a parabola with focus F(_,_) and directrix y=_____ Therefore, the graph of x²=12y is a parabola with focus F(_,_) and a directrix y=_____
141
likes703 views
Answer to a math question The graph of the equation x²= 4py is a parabola with focus F(_,_) and directrix y=_____ Therefore, the graph of x²=12y is a parabola with focus F(_,_) and a directrix y=_____
Miles
4.9114 Answers
The equation x² = 4py represents a parabola that opens upwards if p > 0 or downwards if p < 0. The focus of the parabola is at the point (0, p) and the directrix is the line y = -p.
Therefore, for the equation x² = 12y, we can see that 4p = 12, so p = 3. This means the parabola opens upwards with the focus at the point F(0, 3) and the directrix at the line y = -3.
Frequently asked questions (FAQs)
What is the length of the side opposite the angle θ in a right triangle with an adjacent side of 5 units and a hypotenuse of 13 units?
+
Math question: What is the limit as x approaches 3 of (2x^2 - 12x + 15) / (x - 3)?
+
Math question: Calculate the standard deviation of a data set: {5, 10, 15, 20, 25}, assuming it represents a sample. (
+
New questions in Mathematics