Question
The graph of the equation x²= 4py is a parabola with focus F(_,_) and directrix y=_____ Therefore, the graph of x²=12y is a parabola with focus F(_,_) and a directrix y=_____
141
likes703 views
Answer to a math question The graph of the equation x²= 4py is a parabola with focus F(_,_) and directrix y=_____ Therefore, the graph of x²=12y is a parabola with focus F(_,_) and a directrix y=_____
Miles
4.9114 Answers
The equation x² = 4py represents a parabola that opens upwards if p > 0 or downwards if p < 0. The focus of the parabola is at the point (0, p) and the directrix is the line y = -p.
Therefore, for the equation x² = 12y, we can see that 4p = 12, so p = 3. This means the parabola opens upwards with the focus at the point F(0, 3) and the directrix at the line y = -3.
Frequently asked questions (FAQs)
Math Question: Find the derivative of f(x) = 3x^5 - 2x^3 + 8x - 4.
+
What is the measure of the perpendicular bisector of a side in a triangle with side lengths 5, 12, and 13?
+
Question: Simplify the expression 3x(4y - 2z) - 2(5x - 6y + 3z) using the distributive property.
+
New questions in Mathematics