Question
The graph of the equation x²= 4py is a parabola with focus F(_,_) and directrix y=_____ Therefore, the graph of x²=12y is a parabola with focus F(_,_) and a directrix y=_____
141
likes703 views
Answer to a math question The graph of the equation x²= 4py is a parabola with focus F(_,_) and directrix y=_____ Therefore, the graph of x²=12y is a parabola with focus F(_,_) and a directrix y=_____
Miles
4.9115 Answers
The equation x² = 4py represents a parabola that opens upwards if p > 0 or downwards if p < 0. The focus of the parabola is at the point (0, p) and the directrix is the line y = -p.
Therefore, for the equation x² = 12y, we can see that 4p = 12, so p = 3. This means the parabola opens upwards with the focus at the point F(0, 3) and the directrix at the line y = -3.
Frequently asked questions (FAQs)
What is the vertex form equation of a parabola with a vertex at (2, -3)?
+
What is the maximum or minimum value of the parabola function y = ax^2 if a>0?
+
Math question: Sketch the graph of the quadratic function y = -2x^2 + 4x - 1 over the domain -2 ≤ x ≤ 3. Calculate the maximum value of y. Use
+
New questions in Mathematics