Question
The graph of the equation x²= 4py is a parabola with focus F(_,_) and directrix y=_____ Therefore, the graph of x²=12y is a parabola with focus F(_,_) and a directrix y=_____
141
likes703 views
Answer to a math question The graph of the equation x²= 4py is a parabola with focus F(_,_) and directrix y=_____ Therefore, the graph of x²=12y is a parabola with focus F(_,_) and a directrix y=_____
Miles
4.977 Answers
The equation x² = 4py represents a parabola that opens upwards if p > 0 or downwards if p < 0. The focus of the parabola is at the point (0, p) and the directrix is the line y = -p.
Therefore, for the equation x² = 12y, we can see that 4p = 12, so p = 3. This means the parabola opens upwards with the focus at the point F(0, 3) and the directrix at the line y = -3.
Frequently asked questions (FAQs)
Math question: In △ABC and △DEF, if AB = DE, BC = EF, and ∠ABC = ∠DEF, what can be concluded about the triangles according to the rules of congruence?
+
Question: Consider the logarithmic function y = log(base 2)(x + 1). Plot its graph and determine the x-value when the y-value is equal to 3.
+
Math question: Evaluate sinh(arcsinh(2)).
+
New questions in Mathematics