Suppose that you use 4.29 g of Iron in the chemical reaction: 2Fe(s) + 3 Cu2 + (aq) 2Fe 3 + (aq) + 3Cu(s ) - . What is the theoretical yield of Cu (s), in grams?

To find the theoretical yield of Cu (s), we need to determine the molar ratio between Fe (s) and Cu (s) in the balanced chemical equation.

From the balanced equation:
2Fe(s) + 3Cu2+(aq) → 2Fe3+(aq) + 3Cu(s)

The molar ratio between Fe (s) and Cu (s) is 3:2.

Now, let's calculate the number of moles of Fe (s) used in the reaction:

molar mass of Fe = 55.85 g/mol
moles of Fe (s) = mass of Fe (s) / molar mass of Fe
= 4.29 g / 55.85 g/mol
≈ 0.0767 mol

Using the mole ratio, we can calculate the number of moles of Cu (s) produced:

moles of Cu (s) = (moles of Fe (s) * 3) / 2
= (0.0767 mol * 3) / 2
= 0.115 mol

Finally, to find the theoretical yield of Cu (s) in grams, we can use the molar mass of Cu:

molar mass of Cu = 63.55 g/mol
mass of Cu (s) = moles of Cu (s) * molar mass of Cu
= 0.115 mol * 63.55 g/mol
≈ 7.35 g

Answer: The theoretical yield of Cu (s) is approximately 7.35 grams.