1. Identify the formula for compound interest: A = P \left(1 + \frac{r}{n}\right)^{nt}
- Where:
- \(A\) is the amount of money accumulated after n years, including interest.
- \(P\) is the principal amount (the initial amount).
- \(r\) is the annual interest rate (decimal).
- \(n\) is the number of times that interest is compounded per year.
- \(t\) is the time the money is invested for in years.
2. Substitute the given values into the formula:
- \(P = 8000\),
- \(r = \frac{6}{100} = 0.06\),
- \(n = 12\),
- \(t = 10\).
3. Calculate the compound interest:
A = 8000 \left(1 + \frac{0.06}{12}\right)^{12 \times 10}
4. Compute the value inside the parentheses:
1 + \frac{0.06}{12} = 1 + 0.005 = 1.005
5. Raise the result to the power of \(120\) (since \(12 \times 10 = 120\)):
1.005^{120} \approx 2.040160365
6. Multiply by the principal:
A=8000\times2.040160365\approx14555.17
7. The certificate will be worth $14555.17 after 10 years.