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Problem 9: A right triangle has an angle of 45° and a leg of 12 meters. What is the area of the triangle? (Do not use Heron's theorem)

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Answer to a math question Problem 9: A right triangle has an angle of 45° and a leg of 12 meters. What is the area of the triangle? (Do not use Heron's theorem)

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Madelyn
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1. Identificamos que el triángulo rectángulo tiene un ángulo de 45°, lo que implica que es un triángulo isósceles en el cual los dos catetos son iguales.
2. Dado un cateto de 12 metros, el otro cateto también será de 12 metros.
3. El área de un triángulo rectángulo es:
A = \frac{1}{2} \times \text{base} \times \text{altura}
4. Usando los valores de los catetos:
A = \frac{1}{2} \times 12 \, \text{m} \times 12 \, \text{m}
5. Calculando el área:
A = \frac{1}{2} \times 144 \, \text{m}^2 = 72 \, \text{m}^2

**Resultado final:**
A = 72 \, \text{m}^2

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