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3x 2 5x 2 0

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3x^2-5x+2=0

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Answer to a math question 3x^2-5x+2=0

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${x}_{1,2}=\frac{-(-5)\pm \sqrt{(-5)^{2}-4\cdot 3\cdot 2}}{2\cdot 3}$

${x}_{1,2}=\frac{-(-5)\pm 1}{2\cdot 3}$

${x}_{1}=\frac{-(-5)+1}{2\cdot 3},{x}_{2}=\frac{-(-5)-1}{2\cdot 3}$

$=1$

$=\frac{2}{3}$

$x=1,x=\frac{2}{3}$

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