Question

A field of geysers in Yellowstone may display an eruption between once every 45 minutes, to as much as every 13 hours. Assume the probability is a uniform continuous probability distribution. Find the theoretical average time between eruptions for geysers in this field, and the theoretical standard deviation for these times.

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Answer to a math question A field of geysers in Yellowstone may display an eruption between once every 45 minutes, to as much as every 13 hours. Assume the probability is a uniform continuous probability distribution. Find the theoretical average time between eruptions for geysers in this field, and the theoretical standard deviation for these times.

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Cristian
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119 Answers
1. The eruption times are uniformly distributed between 45 minutes and 13 hours.
2. Convert 45 minutes to hours: 45 \text{ minutes} = \frac{45}{60} = 0.75 \text{ hours}.
3. The random variable X representing eruption times is uniformly distributed on the interval [0.75, 13].
4. The average (mean) of a uniform distribution a to b is calculated as \frac{a + b}{2}.

\text{Mean} = \frac{0.75 + 13}{2} = \frac{13.75}{2} = 6.875 hours.

5. The standard deviation of a uniform distribution from a to b is calculated as \frac{b-a}{\sqrt{12}}.

\text{Standard Deviation} = \frac{13 - 0.75}{\sqrt{12}} = \frac{12.25}{\sqrt{12}} = \frac{12.25}{3.464} \approx 3.5367 hours.

Therefore, the mean eruption time is 6.875 \text{ hours}, and the standard deviation is 3.5367 \text{ hours}.

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